मराठी

If the sum of first 7 terms of an A.P. is 49 and that of its first 17 terms is 289, find the sum of first n terms of the A.P.

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प्रश्न

If the sum of first 7 terms of an A.P. is 49 and that of its first 17 terms is 289, find the sum of first n terms of the A.P.

बेरीज
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उत्तर

Let the first term and the common difference of the given A.P. be a and d, respectively.

Sum of the first 7 terms, S7 = 49

We know

`S = n/2[2a + (n - 1)d]`

⇒ `7/2(2a + 6d) = 49`

⇒ `7/2 xx 2(a + 3d) = 49`

a + 3d = 7     ...(1)

Sum of the first 17 terms, S17 = 289

⇒ `17/2(2a + 16d) = 289`

⇒ `17/2 xx 2(a + 8d) = 289`

a + 8d = `289/17`

a + 8d = 17    ...(2)

Subtracting (2) from (1), we get

5d = 10

d = `5/10`

2

Substituting the value of d in (1), we get

a = 1

Now,

sum of the first n terms is given by

`S_n = n/2[2a + (n - 1)d]`

= `n/2[2 xx 1 + (n - 1) xx 2]`

= `n/2 [2 + 2n - 2]`

= `n/2 [2n]`

= n2

Therefore, the sum of the first n terms of the A.P. is n2.

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