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Suppose a discrete random variable can only take the values 0, 1, and 2. The probability mass function is defined by ,for,,,otherwisef(x)={x2+1k, for x=0, 1, 20, otherwise Find the value of k - Mathematics

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प्रश्न

Suppose a discrete random variable can only take the values 0, 1, and 2. The probability mass function is defined by 
`f(x) = {{:((x^2 + 1)/k","  "for"  x = 0","  1","  2),(0","  "otherwise"):}` 
Find the value of k

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उत्तर

Given f is a probability mass function

`sum_x "f"(x)` = 1

Probability mass function is

x 0 1 2
F(x) `1/k` `2/k` `5/k`

`1/k + 2/k + 5/k` = 1

`8/k` = 1

k = 8

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Types of Random Variables
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पाठ 11: Probability Distributions - Exercise 11.2 [पृष्ठ १९४]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 11 Probability Distributions
Exercise 11.2 | Q 5. (i) | पृष्ठ १९४

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