मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

State whether the following is True or False : The area of the portion lying above the X-axis is positive. - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

State whether the following is True or False :

The area of the portion lying above the X-axis is positive.

पर्याय

  • True

  • False

MCQ
चूक किंवा बरोबर
Advertisements

उत्तर

The area of the portion lying above the X-axis is positive True.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Applications of Definite Integration - Miscellaneous Exercise 7 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 7 Applications of Definite Integration
Miscellaneous Exercise 7 | Q 3.5 | पृष्ठ १५८

संबंधित प्रश्‍न

Find the area of the region bounded by the curve y2 = x and the lines x = 1, x = 4 and the x-axis.


Find the area of the region bounded by the ellipse  `x^2/16 + y^2/9 = 1.`


Find the area under the given curve and given line:

y = x2, x = 1, x = 2 and x-axis


Find the area of the smaller region bounded by the ellipse `x^2/9 + y^2/4` and the line `x/3 + y/2 = 1`


Using the method of integration find the area of the triangle ABC, coordinates of whose vertices are A(2, 0), B (4, 5) and C (6, 3).


Find the equation of an ellipse whose latus rectum is 8 and eccentricity is `1/3`


Find the area of the region. 

{(x,y) : 0 ≤ y ≤ x, 0 ≤ y ≤ x + 2 ,-1 ≤ x ≤ 3} .


Choose the correct alternative :

Area of the region bounded by the curve x2 = y, the X-axis and the lines x = 1 and x = 3 is _______.


Fill in the blank :

Area of the region bounded by x2 = 16y, y = 1, y = 4 and the Y-axis, lying in the first quadrant is _______.


State whether the following is True or False :

The area bounded by the curve x = g (y), Y-axis and bounded between the lines y = c and y = d is given by `int_"c"^"d"x*dy = int_(y = "c")^(y = "d") "g"(y)*dy` 


Solve the following :

Find the area of the region bounded by the curve y = x2 and the line y = 10.


Find the area of the region bounded by y = x2, the X-axis and x = 1, x = 4.


Solve the following:

Find the area of the region bounded by the curve x2 = 25y, y = 1, y = 4 and the Y-axis.


Choose the correct alternative:

Area of the region bounded by the curve x2 = 8y, the positive Y-axis lying in the first quadrant and the lines y = 4 and y = 9 is ______


Choose the correct alternative:

Area of the region bounded by y2 = 16x, x = 1 and x = 4 and the X axis, lying in the first quadrant is ______


The area of the shaded region bounded by two curves y = f(x), and y = g(x) and X-axis is `int_"a"^"b" "f"(x) "d"x + int_"a"^"b" "g"(x)  "d"x`


Find area of the region bounded by the parabola x2 = 4y, the Y-axis lying in the first quadrant and the lines y = 3


The area of the region bounded by the curve y = 4x3 − 6x2 + 4x + 1 and the lines x = 1, x = 5 and X-axis is ____________.


The area enclosed between the curve y = loge(x + e) and the coordinate axes is ______.


`int_0^log5 (e^xsqrt(e^x - 1))/(e^x + 3)` dx = ______ 


`int "e"^x ((sqrt(1 - x^2) * sin^-1 x + 1)/sqrt(1 - x^2))`dx = ________.


The area of the region bounded by the X-axis and the curves defined by y = cot x, `(pi/6 ≤ x ≤ pi/4)` is ______.


Area under the curve `y=sqrt(4x+1)` between x = 0 and x = 2 is ______.


The area included between the parabolas y2 = 4a(x +a) and y2 = 4b(x – a), b > a > 0, is


Find the area between the two curves (parabolas)

y2 = 7x and x2 = 7y.


Area of the region bounded by y= x4, x = 1, x = 5 and the X-axis is ______.


The area (in sq.units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is ______.


The figure shows as triangle AOB and the parabola y = x2. The ratio of the area of the triangle AOB to the area of the region AOB of the parabola y = x2 is equal to ______.


Find the area of the regions bounded by the line y = −2x, the X-axis and the lines x = −1 and x = 2.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×