मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Find the area of the region bounded by y = x2, the X-axis and x = 1, x = 4.

Advertisements
Advertisements

प्रश्न

Find the area of the region bounded by y = x2, the X-axis and x = 1, x = 4.

बेरीज
Advertisements

उत्तर


Given: y = x2

Required area = `int_1^4y*dx`

= `int_1^4 x^2*dx`

= `[x^3/3]_1^4`

= `(1)/(3)(4^3 - 1^3)` 

= `(1)/(3)(64 - 1)`

= `(1)/(3)(63)`

= 21 sq. units.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Applications of Definite Integration - Miscellaneous Exercise 7 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 7 Applications of Definite Integration
Miscellaneous Exercise 7 | Q 4.5 | पृष्ठ १५८

संबंधित प्रश्‍न

Using integration find the area of the triangle formed by positive x-axis and tangent and normal of the circle

`x^2+y^2=4 at (1, sqrt3)`


Find the area of the region bounded by the ellipse `x^2/4 + y^2/9 = 1.`


Find the area of the region bounded by the curve y2 = 4x and the line x = 3


Find the area of the region lying in the first quadrant and bounded by y = 4x2x = 0, y = 1 and = 4


Sketch the graph of y = |x + 3| and evaluate `int_(-6)^0 |x + 3|dx`


Find the area enclosed between the parabola 4y = 3x2 and the straight line 3x - 2y + 12 = 0.


Find the area of the region. 

{(x,y) : 0 ≤ y ≤ x, 0 ≤ y ≤ x + 2 ,-1 ≤ x ≤ 3} .


Using integration find the area of the triangle formed by negative x-axis and tangent and normal to the circle `"x"^2 + "y"^2 = 9  "at" (-1,2sqrt2)`.


Find the area of the region bounded by the following curves, the X-axis and the given lines:  y = x4, x = 1, x = 5


Find the area of the region bounded by the following curves, the X-axis and the given lines:

y = x2 + 1, x = 0, x = 3


Using definite integration, area of the circle x2 + y2 = 49 is _______.


Fill in the blank :

Area of the region bounded by x2 = 16y, y = 1, y = 4 and the Y-axis, lying in the first quadrant is _______.


Fill in the blank :

The area of the region bounded by the curve x2 = y, the X-axis and the lines x = 3 and x = 9 is _______.


Solve the following:

Find the area of the region bounded by the curve x2 = 25y, y = 1, y = 4 and the Y-axis.


Choose the correct alternative:

Area of the region bounded by the curve y = x3, x = 1, x = 4 and the X-axis is ______


State whether the following statement is True or False:

The area of portion lying below the X axis is negative


The area of the circle x2 + y2 = 16 is ______


The area of the region x2 = 4y, y = 1 and y = 2 and the Y axis lying in the first quadrant is ______


Find the area of the region bounded by the curve x = `sqrt(25 - y^2)`, the Y-axis lying in the first quadrant and the lines y = 0 and y = 5


Find the area of the region bounded by the curve y = `sqrt(36 - x^2)`, the X-axis lying in the first quadrant and the lines x = 0 and x = 6


Find the area of the circle x2 + y2 = 16


The ratio in which the area bounded by the curves y2 = 8x and x2 = 8y is divided by the line x = 2 is ______ 


The area of the region bounded by the X-axis and the curves defined by y = cot x, `(pi/6 ≤ x ≤ pi/4)` is ______.


Which equation below represents a parabola that opens upward with a vertex at (0, – 5)?


The area of the circle `x^2 + y^2 = 16`, exterior to the parabola `y = 6x`


The area (in sq.units) of the part of the circle x2 + y2 = 36, which is outside the parabola y2 = 9x, is ______.


The area of the region bounded by the curve y = sin x and the x-axis in [–π, π] is ______.


The area bounded by the curve | x | + y = 1 and X-axis is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×