Advertisements
Advertisements
प्रश्न
State the quotient law of exponents.
Advertisements
उत्तर
The quotient rule tells us that we can divide two powers with the same base by subtracting the exponents. If a is a non-zero real number and m, n are positive integers, then `a^m/a^n = a^(m-n)`
We shall divide the proof into three parts
(i) when m>n
(ii) when m = n
(iii) when m < n
Case 1
When m > n
We have
\[\frac{a^m}{a^n} = \frac{a \times a \times a . . . .\text { to m factors }}{a \times a \times a . . . . \text { to n factors }}\]
\[\frac{a^m}{a^n} = a \times a \times a . . . . to (m - n) \text { factors }\]
\[\frac{a^m}{a^n} = a^{m - n}\]
Case 2
When m = n
We get
`a^m/a^n = a^m/a^m`
Cancelling common factors in numerator and denominator we get,
`a^m/a^n = 1`
By definition we can write 1 as a°
`a^m/a^n = a^(m-m)`
`a^m/a^n = a^(m-n)`
Case 3
When m < n
In this case, we have
`a^m/a^n = 1/(axx axx a ....(n-m))`
`a^m/a^n = 1/(a^(n-m))`
`a^m/a^n = a^-(n-m)`
`a^m/a^n = a^(m-n)`
Hence `a^m/a^n = a^(m-n)`, whether m < n, m = n or,m > n
APPEARS IN
संबंधित प्रश्न
Solve the following equation for x:
`4^(x-1)xx(0.5)^(3-2x)=(1/8)^x`
Assuming that x, y, z are positive real numbers, simplify the following:
`root5(243x^10y^5z^10)`
Show that:
`[{x^(a(a-b))/x^(a(a+b))}div{x^(b(b-a))/x^(b(b+a))}]^(a+b)=1`
If 2x = 3y = 12z, show that `1/z=1/y+2/x`
Find the value of x in the following:
`(13)^(sqrtx)=4^4-3^4-6`
When simplified \[\left( - \frac{1}{27} \right)^{- 2/3}\] is
The value of m for which \[\left[ \left\{ \left( \frac{1}{7^2} \right)^{- 2} \right\}^{- 1/3} \right]^{1/4} = 7^m ,\] is
If \[\frac{2^{m + n}}{2^{n - m}} = 16\], \[\frac{3^p}{3^n} = 81\] and \[a = 2^{1/10}\],than \[\frac{a^{2m + n - p}}{( a^{m - 2n + 2p} )^{- 1}} =\]
If x = \[\frac{2}{3 + \sqrt{7}}\],then (x−3)2 =
If \[\sqrt{13 - a\sqrt{10}} = \sqrt{8} + \sqrt{5}, \text { then a } =\]
