Advertisements
Advertisements
प्रश्न
State de Broglie hypothesis.
Advertisements
उत्तर
The waves associated with moving particles are called matter waves. Matter has both particle nature and wave nature. The wave nature of matter is understood from its wavelength (called de-Broglie wavelength) given by:
λ = `h/p`
or,
λ = `h/(m v)`
Where p is the momentum.
संबंधित प्रश्न
Write the expression for the de Broglie wavelength associated with a charged particle of charge q and mass m, when it is accelerated through a potential V.
An electron and an alpha particle have the same kinetic energy. How are the de Broglie wavelengths associated with them related?
Explain why photoelectric effect cannot be explained on the basis of wave nature of light.
Derive an expression for de Broglie wavelength of electrons.
Describe briefly Davisson – Germer experiment which demonstrated the wave nature of electrons.
How do we obtain characteristic x-ray spectra?
What should be the velocity of the electron so that its momentum equals that of 4000 Å wavelength photon.
Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to 81.9 × 10–15 J.
(Given: mass of proton is 1836 times that of electron).
An electron is accelerated through a potential difference of 81 V. What is the de Broglie wavelength associated with it? To which part of the electromagnetic spectrum does this wavelength correspond?
The ratio between the de Broglie wavelength associated with proton accelerated through a potential of 512 V and that of alpha particle accelerated through a potential of X volts is found to be one. Find the value of X.
