Advertisements
Advertisements
प्रश्न
Write the relationship of de Broglie wavelength λ associated with a particle of mass m in terms of its kinetic energy K.
Advertisements
उत्तर
Kinetic energy of the particle, K = `1/2 "mv"^2 = "P"^2/(2"m")`
p = `sqrt(2"mK")`
de-Broglie wavelength of the particle λ = `"h"/"p" = "h"/sqrt(2"mK")`
APPEARS IN
संबंधित प्रश्न
State de Broglie hypothesis.
Why we do not see the wave properties of a baseball?
A proton and an electron have the same kinetic energy. Which one has a greater de Broglie wavelength? Justify.
What is Bremsstrahlung?
Explain why photoelectric effect cannot be explained on the basis of wave nature of light.
Derive an expression for de Broglie wavelength of electrons.
Describe briefly Davisson – Germer experiment which demonstrated the wave nature of electrons.
How do we obtain characteristic x-ray spectra?
What should be the velocity of the electron so that its momentum equals that of 4000 Å wavelength photon.
Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to 81.9 × 10–15 J.
(Given: mass of proton is 1836 times that of electron).
