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Solve the following system of equations by matrix method:  x + y + z = 6 x + 2z = 7 3x + y + z = 12 - Mathematics

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प्रश्न

Solve the following system of equations by matrix method:
 x + y + z = 6
x + 2z = 7
3x + y + z = 12

बेरीज
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उत्तर

 x + y + z = 6
x + 2z = 7
3x + y + z = 12

AX = B

`A = [(1,1,1),(1,0,2),(3,1,1)], X = [(x),(y),(z)], B = [(6),(7),(12)]`

X = A−1B

`A^-1 = 1/|A| . adj(A)`

`A = [(1,1,1),(1,0,2),(3,1,1)]`

Use cofactor expansion along the first row:

`|A| = 1 . |(0,2),(1,1)|-1. |(1,2),(3,1)| +1.|(1,0),(3,1)|`

Now calculate each 2 × 2 determinant:

`|(0,2),(1,1)| = 0(1)-2(1) = -2`

`|(1,2),(3,1)| = 1(1) -2(3) = 1-6=-5`

`|(1,0),(3,1)| = 1(1) - 0(3) = 1`

∣A∣ = 1(−2)−1 (−5) + 1(1) = −2 + 5 + 1 = 4

We already computed these minors earlier, but here’s the full cofactor matrix:

`Cof(A) = [(-2,5,1),(0,0,-2),(2,-1,-1)]`

adj(A) = Cof(A)T = `[(-2,0,2),(5,0,-1),(1,-2,-1)]`

`A^-1 = 1/4 . [(-2,0,2),(5,0,-1),(1,-2,-1)]`

X = A−1B = `1/4 [(-2,0,2),(5,0,-1),(1,-2,-1)] . [(6),(7),(12)]`

(−2) (6) + (0) (7) + (2) (12) = −12 + 0 + 24 = 12

(5) (6) + (0) (7) + (−1) (12) = 30 + 0 −12 = 18

(1) (6) + (−2) (7) + (−1) (12) = 6 − 14 − 12 = −20

`X = 1/4 . [(12),(18),(-20)] = [(3),(4.5),(-5)]`

x = 2, y = 1, z = 3

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पाठ 8: Solution of Simultaneous Linear Equations - Exercise 8.1 [पृष्ठ १४]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 8 Solution of Simultaneous Linear Equations
Exercise 8.1 | Q 2.12 | पृष्ठ १४

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