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प्रश्न
Solve the following problem:
Write the following number in ordinary decimal form:
3.49 × 10−11
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उत्तर
3.49 × 10−11 = 0.0000000000349
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संबंधित प्रश्न
To make a saturated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 K. Find its concentration at this temperature.
A sample of drinking water was found to be severely contaminated with chloroform, CHCl3, supposed to be carcinogenic in nature. The level of contamination was 15 ppm (by mass).
- Express this in percent by mass.
- Determine the molality of chloroform in the water sample.
To make a saturated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 K. Find its concentration at this temperature.
Why does the molarity of a solution depend upon temperature?
Solve the following problem:
Find out the molar mass of the following compounds:
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Write the following number in ordinary decimal form:
14.3 × 10−2
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Write the following number in ordinary decimal form:
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Write the following number in ordinary decimal form:
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Perform each of the following calculations. Round off your answers to three digits.
(3.26104) (1.54106)
Perform the following calculation. Round off your answer to three digits.
(8.39 107) (4.53 109)
Solve the following problem:
Perform the following calculation. Round off your answer to three digits.
`((9.28xx10^9)(9.9xx10^-7))/((511)(2.98xx10^-6))`
Name the process associated with the following
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Name a lustrous non-metal.
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(ii) Name the technique used by the child.
(iii) Suggest one more application of this technique.

If 500 mL of a 5 M solution is diluted to 1500 mL, what will be the molarity of the solution obtained?
What will be the molality of the solution containing 18.25 g of \[\ce{HCl}\] gas in 500 g of water?
Sulphuric acid reacts with sodium hydroxide as follows:
\[\ce{H2SO4 + 2NaOH -> Na2SO4 + 2H2O}\]
When 1 L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained is:
(i) 0.1 mol L–1
(ii) 7.10 g
(iii) 0.025 mol L–1
(iv) 3.55 g
Which of the following solutions have the same concentration?
(i) \[\ce{20 g of NaOH in 200 mL of solution}\]
(ii) \[\ce{0.5 mol of KCl in 200 mL of solution}\]
(iii) \[\ce{40 g of NaOH in 100 mL of solution}\]
(iv) \[\ce{20 g of KOH in 200 mL of solution}\]
Which of the following terms are unitless?
(i) Molality
(ii) Molarity
(iii) Mole fraction
(iv) Mass percent
If 4 g of \[\ce{NaOH}\] dissolves in 36 g of \[\ce{H2O}\], calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1g mL–1).
The molarity of pure water is ______.
With increase of temperature, which of these changes?
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250 g solution of D-glucose in water contains 10.8% of carbon by weight. The molality of the solution is nearest to ______.
(Given: Atomic weights are H, 1u; C, 12u; O, 16u)
The molality of solution containing 15.20 g of urea, (molar mass = 60) dissolved in 150 g or water is ______.
