Advertisements
Advertisements
प्रश्न
Solve the following pairs of equations:
`(3)/(5) x - (2)/(3) y + 1` = 0
`(1)/(3) y + (2)/(5) x ` = 4
Advertisements
उत्तर
`(3)/(5) x - (2)/(3) y + 1` = 0
⇒ 9x - 10y + 15 = 0
⇒ 9x - 10y = -15 ....(i)
`(1)/(3)y + (2)/(5)x` = 4
⇒ 5y + 6x = 60
⇒ 6x + 5y = 60 ....(ii)
Multiplying eqn. (ii) by 2, we get
12x + 10y = 120 ....(iii)
Adding eqns. (i) and (iii), we get
21x = 105
⇒ x = 5
Substituting the value of x in eqn. (ii), we get
6(5) + 5y = 60
⇒ 30 + 5y = 60
⇒ 5y = 30
⇒ y = 6
Thus, the solution set is (5,6).
APPEARS IN
संबंधित प्रश्न
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
13 + 2y = 9x
3y = 7x
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
`[ x - y ]/6 = 2( 4 - x )`
2x + y = 3( x - 4 )
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
2x − 3y − 3 = 0
`[2x]/3 + 4y + 1/2` = 0
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
41x + 53y = 135
53x + 41y = 147
Solve the following simultaneous equations:
65x - 33y = 97
33x - 65y = 1
Solve the following pairs of equations:
`(2)/x + (3)/y = (9)/(xy)`
`(4)/x + (9)/y = (21)/(xy)`
Where x ≠ 0, y ≠ 0
Solve the following pairs of equations:
`(xy)/(x + y) = (6)/(5)`
`(xy)/(y - x)` = 6
Where x + y ≠ 0 and y - x ≠ 0
If 2x + y = 23 and 4x - y = 19 : find the value of x - 3y and 5y - 2x.
Salman and Kirti start at the same time from two places 28 km apart. If they walk in the same direction, Salman overtakes Kirti in 28 hours but if they walk in the opposite directions, they meet in 4 hours. Find their speeds (in km/h).
Sunil and Kafeel both have some oranges. If Sunil gives 2 oranges to Kafeel, then Kafeel will have thrice as many as Sunil. And if Kafeel gives 2 oranges to Sunil, then they will have the same numbers of oranges. How many oranges does each have?
