Advertisements
Advertisements
प्रश्न
Anil and Sunita have incomes in the ratio 3 : 5. If they spend in the ratio 1 : 3, each saves T 5000. Find the income of each.
Advertisements
उत्तर
Let Anil's income = Rs. x and Sunita's income = Rs. y
According to given information, we have
`x/y = (3)/(5)`
⇒ 5x = 3y
⇒ 5x - 3y = 0 ....(i)
And,
`(x - 5000)/(y - 5000) = (1)/(3)` ....[Expense = Income - Saving]
⇒ 3x - 15000 = y - 5000
⇒ 3x - y = 10000 ....(ii)
Multiplying eqn. (ii) by 3, we get
9x - 3y = 30000 ....(iii)
Subtracting eqn. (i) from (iii), we get
4x = 30000
⇒ x = 7500
⇒ 5(7500) - 3y = 0
⇒ 37500 - 3y = 0
⇒ 3y = 37500
⇒ y = 12500
Hence, Anil's income is Rs.7500 and Sunita's income is Rs.12,500.
APPEARS IN
संबंधित प्रश्न
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
13 + 2y = 9x
3y = 7x
For solving pair of equation, in this exercise use the method of elimination by equating coefficients :
3x - y = 23
`x/3 + y/4 = 4`
If 2x + y = 23 and 4x - y = 19; find the values of x - 3y and 5y - 2x.
Solve :
`[ 7 + x ]/5 - [ 2x - y ]/4 = 3y - 5`
`[5y - 7]/2 + [ 4x - 3 ]/6 = 18 - 5x`
Solve the following simultaneous equations:
13a - 11b = 70
11a - 13b = 74
Solve the following pairs of equations:
`(3)/(5) x - (2)/(3) y + 1` = 0
`(1)/(3) y + (2)/(5) x ` = 4
Solve the following pairs of equations:
`(xy)/(x + y) = (6)/(5)`
`(xy)/(y - x)` = 6
Where x + y ≠ 0 and y - x ≠ 0
In a two-digit number, the sum of the digits is 7. The difference of the number obtained by reversing the digits and the number itself is 9. Find the number.
If 2 is added to the numerator and denominator it becomes `(9)/(10)` and if 3 is subtracted from the numerator and denominator it becomes `(4)/(5) `Find the fraction.
The present ages of Kapil and Karuna are in the ratio 2 : 3. Six years later, the ratio will be 5 : 7. Find their present ages.
