मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

Solve the following : Find the area of the region bounded by the curve y = x2 and the line y = 10. - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Solve the following :

Find the area of the region bounded by the curve y = x2 and the line y = 10.

बेरीज
Advertisements

उत्तर

Given equation of the curve is
y = x2
∴ x = `sqrt(y)`    ...[∵ In first quadrant, x> 0]

Required area = area of the region ORQPO
= 2 (area of the region ORQO)

= `2 int_0^10x*dy`

= `2int_0^10 y^(1/2)*dy`

= `2[y^(3/2)/(3/2)]_0^10`

= `(4)/(3)[(10)^(3/2) - 0]`

= `(4)/(3)(10sqrt(10))`

= `(40sqrt(10))/(3)"sq.units"`.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Applications of Definite Integration - Miscellaneous Exercise 7 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 7 Applications of Definite Integration
Miscellaneous Exercise 7 | Q 4.3 | पृष्ठ १५८

संबंधित प्रश्‍न

Find the area of the region in the first quadrant enclosed by the x-axis, the line y = x and the circle x2 + y2 = 32.


Using integration find the area of the region {(x, y) : x2+y2 2ax, y2 ax, x, y  0}.


Find the area of the region bounded by y2 = 9x, x = 2, x = 4 and the x-axis in the first quadrant.


Find the area of the region bounded by x2 = 4yy = 2, y = 4 and the y-axis in the first quadrant.


Find the area of the region in the first quadrant enclosed by x-axis, line x = `sqrt3` y and the circle x2 + y2 = 4.


Find the area of the region bounded by the curve y2 = 4x and the line x = 3


Area of the region bounded by the curve y2 = 4x, y-axis and the line y = 3 is ______.


Using the method of integration find the area of the triangle ABC, coordinates of whose vertices are A(2, 0), B (4, 5) and C (6, 3).


Find the equation of an ellipse whose latus rectum is 8 and eccentricity is `1/3`


Using integration, find the area of the region {(x, y) : x2 + y2 ≤ 1 ≤ x + y}.


Find the area of the smaller region bounded by the ellipse \[\frac{x^2}{9} + \frac{y^2}{4} = 1\] and the line \[\frac{x}{3} + \frac{y}{2} = 1 .\]


Find the area of the region bounded by the following curves, the X-axis and the given lines: y = `sqrt(16 - x^2)`, x = 0, x = 4


State whether the following is True or False :

The area bounded by the curve x = g (y), Y-axis and bounded between the lines y = c and y = d is given by `int_"c"^"d"x*dy = int_(y = "c")^(y = "d") "g"(y)*dy` 


Solve the following :

Find the area of the region bounded by the curve xy = c2, the X-axis, and the lines x = c, x = 2c.


Choose the correct alternative:

Area of the region bounded by y2 = 16x, x = 1 and x = 4 and the X axis, lying in the first quadrant is ______


State whether the following statement is True or False:

The area bounded by the curve y = f(x) lies on the both sides of the X-axis is `|int_"a"^"b" "f"(x)  "d"x| + |int_"b"^"c" "f"(x)  "d"x|`


State whether the following statement is True or False:

The equation of the area of the circle is `x^2/"a"^2 + y^2/"b"^2` = 1


The area bounded by the parabola x2 = 9y and the lines y = 4 and y = 9 in the first quadrant is ______


Find the area of the circle x2 + y2 = 62 


If `int_0^(pi/2) log (cos x) "dx" = - pi/2 log 2,` then `int_0^(pi/2) log (cosec x)`dx = ?


The area of the region bounded by the curve y = 4x3 − 6x2 + 4x + 1 and the lines x = 1, x = 5 and X-axis is ____________.


The area enclosed by the parabolas x = y2 - 1 and x = 1 - y2 is ______.


Equation of a common tangent to the circle, x2 + y2 – 6x = 0 and the parabola, y2 = 4x, is:


Area of the region bounded by y= x4, x = 1, x = 5 and the X-axis is ______.


The area of the region bounded by the curve y = sin x and the x-axis in [–π, π] is ______.


The area (in sq. units) of the region {(x, y) : y2 ≥ 2x and x2 + y2 ≤ 4x, x ≥ 0, y ≥ 0} is ______.


The area bounded by the curve | x | + y = 1 and X-axis is ______.


If the area enclosed by y = f(x), X-axis, x = a, x = b and y = g(x), X-axis, x = a, x = b are equal, then f(x) = g(x).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×