Advertisements
Advertisements
प्रश्न
Solve the following equation by factorization
`(2)/(x^2) - (5)/x + 2 = 0, x ≠ 0`
Advertisements
उत्तर
`(2)/(x^2) - (5)/x + 2 = 0, x ≠ 0`
⇒ 2 - 5x + 2x2 = 0
⇒ 2x2 - 5x + 2 = 0 ...`{(∵ 2 xx 2 = 4),(4 = -4 xx (-1)),(-5 = -4 - 1):}}`
⇒ 2x2 - 4x - x + 2 = 0
⇒ 2x(x - 2) - 1(x - 2) = 0
⇒ (x - 2) (2x - 1) = 0
Either x - 2 = 0,
then x = 2
or
2x = 1 = 0,
then 2x = 1
⇒ x = `(1)/(2)`
∴ x = 2, `(1)/(2)`.
APPEARS IN
संबंधित प्रश्न
The product of Ramu's age (in years) five years ago and his age (in years) nice years later is 15. Determine Ramu's present age.
Solve the following quadratic equations by factorization:
`x^2 – (a + b) x + ab = 0`
Determine whether the values given against the quadratic equation are the roots of the equation.
2m2 – 5m = 0, m = 2, `5/2`
If 1 is a root of the quadratic equation \[3 x^2 + ax - 2 = 0\] and the quadratic equation \[a( x^2 + 6x) - b = 0\] has equal roots, find the value of b.
Solve the following equation: 2x2 - x - 6 = 0
Solve the equation:
`6(x^2 + (1)/x^2) -25 (x - 1/x) + 12 = 0`.
In each of the following determine whether the given values are solutions of the equation or not.
3x2 - 2x - 1 = 0; x = 1
In each of the following, determine whether the given values are solution of the given equation or not:
`a^2x^2 - 3abx + 2b^2 = 0; x = a/b, x = b/a`.
A piece of cloth costs Rs. 300. If the piece was 5 metres longer and each metre of cloth costs Rs. 2 less, the cost of the piece would have remained unchanged. How long is the original piece of cloth and what is the rate per metre?
The polynomial equation x(x + 1) + 8 = (x + 2) (x – 2) is:
