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Solve the Following Quadratic Equations by Factorization: 4x2 + 4bx - (A2 - B2) = 0 - Mathematics

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प्रश्न

Solve the following quadratic equations by factorization:

4x2 + 4bx - (a2 - b2) = 0

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उत्तर

4x2 + 4bx - (a2 - b2) = 0

4x2 + 2(a + b)x - 2(a - b)x - (a2 - b2) = 0

2x(2x + a + b) - (a - b)(2x + a + b) = 0

(2x - (a - b))(2x + a + b) = 0

Therefore,

2x - (a - b) = 0

2x = a - b

`x=(a-b)/2`

or,

2x + a + b = 0

2x = -(a + b)

`x=(-(a+b))/2`

Hence, `x=(a-b)/2` or `x=(-(a+b))/2`

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पाठ 4: Quadratic Equations - Exercise 4.3 [पृष्ठ १९]

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आरडी शर्मा Mathematics [English] Class 10
पाठ 4 Quadratic Equations
Exercise 4.3 | Q 18 | पृष्ठ १९

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