Advertisements
Advertisements
प्रश्न
Solve:
`1/p + 1/q + 1/x = 1/(x + p + q)`
Advertisements
उत्तर
`1/p + 1/q + 1/x = 1/(x + p + q)`
`=> 1/p + 1/q + 1/x - 1/(x + p + q) = 0`
`=> (q + p)[1/(pq) + 1/(x^2 + px + qx)] = 0`
`=> (p + q) [(x^2 + px + qx + pq)/(pq(x^2 + px + qx))] = 0`
`=>` x2 + px + qx + pq = 0
`=>` x(x + p) + q(x + p) = 0
`=>` (x + p)(x + q) = 0
`=>` x = – p and x = – q
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation by factorization method : `3x^2-29x+40=0`
Solve the following quadratic equations by factorization:
48x2 − 13x − 1 = 0
`3x^2-x-2=0`
If the sum and product of the roots of the equation kx2 + 6x + 4k = 0 are real, then k =
Solve the following equation: abx2 +(b2-ac) x - bc = 0
The sum of the square of two numbers is 233. If one of the numbers is 3 less than twice the other number. Find the numbers.
Write the number of zeroes in the end of a number whose prime factorization is 22 × 53 × 32 × 17.
Solve the following equation by factorization
3(y2 – 6) = y(y + 7) – 3
Mohini wishes to fit three rods together in the shape of a right triangle. If the hypotenuse is 2 cm longer than the base and 4 cm longer than the shortest side, find the lengths of the rods.
Solve the following equation by factorisation :
`sqrt(3)x^2 + 10x + 7sqrt(3)` = 0
