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प्रश्न
Show that the energy required to build up the current I in a coil of inductance L is `1/2 LI^2`.
संख्यात्मक
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उत्तर
The work done against the back/induced emf is stored as magnetic potential energy.
The rate of work done, when a current i is passing through the coil, is:
`(dW)/dt = |epsilon|I = (L (dI)/dt)I`
∴ W = ∫dW
= `int_0^1`LIdl
= `1/2 LI^2`
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