मराठी

Read the following passage and answer the questions given below: The relation between the height of the plant ('y' in cm) with respect to its exposure to the sunlight is governed by the following

Advertisements
Advertisements

प्रश्न

Read the following passage and answer the questions given below:

The relation between the height of the plant ('y' in cm) with respect to its exposure to the sunlight is governed by the following equation y = `4x - 1/2 x^2`, where 'x' is the number of days exposed to the sunlight, for x ≤ 3.

  1. Find the rate of growth of the plant with respect to the number of days exposed to the sunlight.
  2. Does the rate of growth of the plant increase or decrease in the first three days? What will be the height of the plant after 2 days?
बेरीज
Advertisements

उत्तर

y = `4x - 1/2 x^2`

i. The rate of growth of the plant with respect to the number of days exposed to sunlight is given by `dy/dx` = 4 – x.

ii. Let rate of growth be represented by the function g(x) = `dy/dx`.

Now, g'(x) = `d/dx(dy/dx)` = –1 < 0.

`\implies` g(x) decreases.

So the rate of growth of the plant decreases for the first three days.

Height of the plant after 2 days is y = `4 xx 2 - 1/2(2)^2` = 6 cm.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2023-2024 (March) Board Sample Paper

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

If x cos(a+y)= cosy then prove that `dy/dx=(cos^2(a+y)/sina)`

Hence show that `sina(d^2y)/(dx^2)+sin2(a+y)(dy)/dx=0`


Find the second order derivative of the function.

ex sin 5x


If y = 500e7x + 600e–7x, show that `(d^2y)/(dx^2)` = 49y.


If x7 . y9 = (x + y)16 then show that `"dy"/"dx" = "y"/"x"`


Find `("d"^2"y")/"dx"^2`, if y = `"x"^5`


Find `("d"^2"y")/"dx"^2`, if y = `"e"^"log x"`


Find `("d"^2"y")/"dx"^2`, if y = `"e"^((2"x" + 1))`.


Find `("d"^2"y")/"dx"^2`, if y = log (x).


If ax2 + 2hxy + by2 = 0, then show that `("d"^2"y")/"dx"^2` = 0


`sin xy + x/y` = x2 – y


tan–1(x2 + y2) = a


If x sin (a + y) + sin a cos (a + y) = 0, prove that `"dy"/"dx" = (sin^2("a" + y))/sin"a"`


If y = tan–1x, find `("d"^2y)/("dx"^2)` in terms of y alone.


If x2 + y2 + sin y = 4, then the value of `(d^2y)/(dx^2)` at the point (–2, 0) is ______.


If y = `sqrt(ax + b)`, prove that `y((d^2y)/dx^2) + (dy/dx)^2` = 0.


`"Find"  (d^2y)/(dx^2)  "if"  y=e^((2x+1))`


Find `(d^2y)/dx^2` if, `y = e^((2x + 1))`


Find `(d^2y)/dx^2` if, `y = e^((2x + 1))`


Find `(d^2y)/dx^2` if, `y = e^((2x+1))`


Let \[y=f(x)\]. What is the first derivative of \[y\] with respect to \[x\]?


Which expression defines the second order derivative of \[y\] with respect to \[x\]?


If \[y=\mathrm{A}\sin x+\mathrm{B}\cos x\], what is \[\frac{dy}{dx}\]?


Which equation is equivalent to \[\frac{dy}{dx}=\frac{1}{\sqrt{1-x^2}}\] for \[y=\sin^{-1}x\]?


After differentiating \[\sqrt{1-x^2}\cdot\frac{dy}{dx}=1\], which equation results?


What is \[\frac{d}{dx}\left(\sqrt{1-x^2}\right)\] in the differentiation for \[y=\sin^{-1}x\]?


Differentiating \[(1-x^2)y_{1}^{2}=1\] gives which expression?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×