मराठी

Rationalise the denominator: 6/(sqrt(5) – sqrt(3)) - Mathematics

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प्रश्न

Rationalise the denominator:

`6/(sqrt(5) - sqrt(3))`

बेरीज
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उत्तर

We are asked to rationalise the denominator `6/(sqrt(5) - sqrt(3))`

Step 1: Multiply numerator and denominator by the conjugate of the denominator:

`6/(sqrt(5) - sqrt(3)) xx (sqrt(5) + sqrt(3))/(sqrt(5) + sqrt(3))`

= `(6(sqrt(5) + sqrt(3)))/((sqrt(5) - sqrt(3))(sqrt(5) + sqrt(3))`

Step 2: Simplify the denominator using (a – b)(a + b) = a2 – b2:

`(sqrt(5))^2 - (sqrt(3))^2`

= 5 – 3

= 2

Step 3: Final expression:

`(6(sqrt(5) + sqrt(3)))/2`

= `3(sqrt(5) + sqrt(3))`

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: Rational and Irrational Numbers - MISCELLANEOUS EXERCISE [पृष्ठ १७]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 1 Rational and Irrational Numbers
MISCELLANEOUS EXERCISE | Q 4. (vii) | पृष्ठ १७
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