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प्रश्न
Prove that sec2 (90° - θ) + tan2 (90° - θ) = 1 + 2 cot2 θ.
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उत्तर
LHS = sec2 (90° - θ) + tan2 (90° - θ)
= cosec2θ + cot2θ
= 1 + cot2θ + cot2θ
= 1 + 2cot2θ
= RHS
Hence proved.
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