मराठी

Prove that cot x cot 2x – cot 2x cot 3x – cot 3x cot x = 1

Advertisements
Advertisements

प्रश्न

Prove the following:

cot x cot 2x – cot 2x cot 3x – cot 3x cot x = 1

बेरीज
Advertisements

उत्तर

cot 3x = cot(2x + x) = `(cot 2x  cot x-1)/(cot x + cot 2x)`  `[∵ cot (A + B) = (cot A cot B - 1)/(cot A + cot B)]`

⇒ cot 3x (cot x + cot 2x) = cot 2x cot x - 1

⇒ cot 3x cot x + cot 3x cot 2x = cot 2x cot x - 1

⇒ cot x cot 2x - cot 2x cot 3x - cot 3x cot x = 1

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometric Functions - EXERCISE 3.3 [पृष्ठ ६८]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
पाठ 3 Trigonometric Functions
EXERCISE 3.3 | Q 22. | पृष्ठ ६८

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Find the value of: sin 75°


Prove the following: `(tan(pi/4 + x))/(tan(pi/4 - x)) = ((1+ tan x)/(1- tan x))^2`


Prove the following:

`cos ((3pi)/ 2 + x ) cos(2pi + x) [cot ((3pi)/2 - x) + cot (2pi + x)]= 1`


Prove the following:

sin 2x + 2sin 4x + sin 6x = 4cos2 x sin 4x


Prove the following:

`(sin 5x + sin 3x)/(cos 5x + cos 3x) = tan 4x`


Prove that: sin x + sin 3x + sin 5x + sin 7x = 4 cos x cos 2x sin 4x


If \[\sin A = \frac{4}{5}\] and \[\cos B = \frac{5}{13}\], where 0 < A, \[B < \frac{\pi}{2}\], find the value of the following:

cos (A + B)


If \[\cos A = - \frac{24}{25}\text{ and }\cos B = \frac{3}{5}\], where π < A < \[\frac{3\pi}{2}\text{ and }\frac{3\pi}{2}\]< B < 2π, find the following:
sin (A + B)


If \[\sin A = \frac{1}{2}, \cos B = \frac{12}{13}\], where \[\frac{\pi}{2}\]< A < π and \[\frac{3\pi}{2}\] < B < 2π, find tan (A − B).


If \[\sin A = \frac{1}{2}, \cos B = \frac{\sqrt{3}}{2}\], where \[\frac{\pi}{2}\] < A < π and 0 < B < \[\frac{\pi}{2}\], find the following:
tan (A + B)


If \[\cos A = - \frac{12}{13}\text{ and }\cot B = \frac{24}{7}\], where A lies in the second quadrant and B in the third quadrant, find the values of the following:
sin (A + B)


Prove that:

\[\sin\left( \frac{\pi}{3} - x \right)\cos\left( \frac{\pi}{6} + x \right) + \cos\left( \frac{\pi}{3} - x \right)\sin\left( \frac{\pi}{6} + x \right) = 1\]

 


Prove that \[\frac{\tan 69^\circ + \tan 66^\circ}{1 - \tan 69^\circ \tan 66^\circ} = - 1\].


Prove that:
\[\frac{\sin \left( A - B \right)}{\cos A \cos B} + \frac{\sin \left( B - C \right)}{\cos B \cos C} + \frac{\sin \left( C - A \right)}{\cos C \cos A} = 0\]

 


Prove that:
cos2 A + cos2 B − 2 cos A cos B cos (A + B) = sin2 (A + B)


Prove that:
tan 8x − tan 6x − tan 2x = tan 8x tan 6x tan 2x


If x lies in the first quadrant and \[\cos x = \frac{8}{17}\], then prove that:

\[\cos \left( \frac{\pi}{6} + x \right) + \cos \left( \frac{\pi}{4} - x \right) + \cos \left( \frac{2\pi}{3} - x \right) = \left( \frac{\sqrt{3} - 1}{2} + \frac{1}{\sqrt{2}} \right)\frac{23}{17}\]

 


If α, β are two different values of x lying between 0 and 2π, which satisfy the equation 6 cos x + 8 sin x = 9, find the value of sin (α + β).

 

If sin α + sin β = a and cos α + cos β = b, show that

\[\sin \left( \alpha + \beta \right) = \frac{2ab}{a^2 + b^2}\]

 


Prove that:
\[\frac{1}{\sin \left( x - a \right) \sin \left( x - b \right)} = \frac{\cot \left( x - a \right) - \cot \left( x - b \right)}{\sin \left( a - b \right)}\]


Find the maximum and minimum values of each of the following trigonometrical expression:

sin x − cos x + 1


Reduce each of the following expressions to the sine and cosine of a single expression: 

\[\sqrt{3} \sin x - \cos x\] 


Prove that \[\left( 2\sqrt{3} + 3 \right) \sin x + 2\sqrt{3} \cos x\]  lies between \[- \left( 2\sqrt{3} + \sqrt{15} \right) \text{ and } \left( 2\sqrt{3} + \sqrt{15} \right)\]


If x cos θ = y cos \[\left( \theta + \frac{2\pi}{3} \right) = z \cos \left( \theta + \frac{4\pi}{3} \right)\]then write the value of \[\frac{1}{x} + \frac{1}{y} + \frac{1}{z}\] 


If 12 sin x − 9sin2 x attains its maximum value at x = α, then write the value of sin α.


If tan \[\alpha = \frac{1}{1 + 2^{- x}}\] and \[\tan \beta = \frac{1}{1 + 2^{x + 1}}\] then write the value of α + β lying in the interval \[\left( 0, \frac{\pi}{2} \right)\] 


If cot (α + β) = 0, sin (α + 2β) is equal to


If tan θ1 tan θ2 = k, then \[\frac{\cos \left( \theta_1 - \theta_2 \right)}{\cos \left( \theta_1 + \theta_2 \right)} =\]


The value of cos (36° − A) cos (36° + A) + cos (54° + A) cos (54° − A) is


If tan 69° + tan 66° − tan 69° tan 66° = 2k, then k =


If \[\tan\alpha = \frac{x}{x + 1}\] and \[\tan\alpha = \frac{x}{x + 1}\], then \[\alpha + \beta\] is equal to


Find the most general value of θ satisfying the equation tan θ = –1 and cos θ = `1/sqrt(2)`.


Find the general solution of the equation `(sqrt(3) - 1) costheta + (sqrt(3) + 1) sin theta` = 2

[Hint: Put `sqrt(3) - 1` = r sinα, `sqrt(3) + 1` = r cosα which gives tanα = `tan(pi/4 - pi/6)` α = `pi/12`]


If tan θ = 3 and θ lies in third quadrant, then the value of sin θ  ______.


If tanα = `1/7`, tanβ = `1/3`, then cos2α is equal to ______.


If sinx + cosx = a, then |sinx – cosx| = ______.


The maximum distance of a point on the graph of the function y = `sqrt(3)` sinx + cosx from x-axis is ______.


State whether the statement is True or False? Also give justification.

If tanA = `(1 - cos B)/sinB`, then tan2A = tanB


State whether the statement is True or False? Also give justification.

If tanθ + tan2θ + `sqrt(3)` tanθ tan2θ = `sqrt(3)`, then θ = `("n"pi)/3 + pi/9`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×