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Prove that cos 5θ = 16 cos5θ – 20 cos3θ + 5 cos θ

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प्रश्न

Prove that cos 5θ = 16 cos5θ – 20 cos3θ + 5 cos θ

बेरीज
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उत्तर

cos5θ = cos(2θ + 3θ)

= cos 2θ cos 3θ – sin 2θ sin 3θ

= (2 cos2θ – 1)(4 cos3θ – 3 cos θ) – 2 sin θ cos θ(3 sin θ – 4 sin3θ)

= 8cos5θ – 6 cos3θ – 4 cos3θ + 3 cos θ – 6 sin2θ cos θ + 8 cos θ sin4θ

= 8 cos5θ – 6 cos3θ – 4 cos3θ + 3 cos θ – 6(1 – cos2θ) cos θ + 8 cos θ(1 – cos2θ)2

= 8 cos5θ – 6 cos3θ – 4 cos3θ + 3 cos θ – 6 cos θ + 6 cos3θ + 8 cos 0(1+ cos4θ – 2 cos2θ)

= 8 cos5θ – 6 cos3θ – 4 cos3θ + 3 cos θ – 6 cos θ + 6 cos3θ + 8 cos θ + 8 cos5θ – 16 cos3θ

= 16 cos5θ – 20 cos3θ + 5 cos θ

= R.H.S

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Trigonometric Functions and Their Properties
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.5 [पृष्ठ ११८]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.5 | Q 4 | पृष्ठ ११८

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