मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Obtain approximately the ratio of the nuclear radii of the gold isotope Au97197Au and the silver isotope Ag47197Ag.

Advertisements
Advertisements

प्रश्न

Obtain approximately the ratio of the nuclear radii of the gold isotope `""_97^197 "Au"` and the silver isotope `""_47^197"Ag"`.

संख्यात्मक
Advertisements

उत्तर

Nuclear radius of the gold isotope `""_79"Au"^197` = RAu

Nuclear radius of the silver isotope `""_47"Ag"^107` = RAg

Mass number of gold, AAu = 197

Mass number of silver, AAg = 107

The ratio of the radii of the two nuclei is related with their mass numbers as:

`"R"_"Au"/"R"_"Ag" = ("R"_"Au"/"R"_"Ag")^(1/3)`

`= (197/107)^(1/3) = 1.2256`

Hence, the ratio of the nuclear radii of the gold and silver isotopes is about 1.23.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Nuclei - Exercise [पृष्ठ ४६३]

APPEARS IN

एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 13 Nuclei
Exercise | Q 11 | पृष्ठ ४६३
एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 13 Nuclei
Exercise | Q 13.11 | पृष्ठ ४६३

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Two stable isotopes of lithium `""_3^6"Li"` and `""_3^7"Li"` have respective abundances of 7.5% and 92.5%. These isotopes have masses 6.01512 u and 7.01600 u, respectively. Find the atomic mass of lithium.


The three stable isotopes of neon: `""_10^20"Ne"`, `""_10^21"Ne"` and `""_10^22"Ne"` have respective abundances of 90.51%, 0.27% and 9.22%. The atomic masses of the three isotopes are 19.99 u, 20.99 u and 21.99 u, respectively. Obtain the average atomic mass of neon.


The nucleus `""_10^23"Ne"` decays by `beta^(-)`emission. Write down the β decay equation and determine the maximum kinetic energy of the electrons emitted. Given that:

`"m"(""_10^23 "Ne")` = 22.994466 u

`"m"(""_11^23 "Na")` = 22.989770 u.


In a periodic table the average atomic mass of magnesium is given as 24.312 u. The average value is based on their relative natural abundance on earth. The three isotopes and their masses are `""_12^24Mg` (23.98504u),  `""_12^25 Mg` (24.98584u) and `""_12^26Mg` (25.98259u). The natural abundance of `""_12^24 Mg` is 78.99% by mass. Calculate the abundances of other two isotopes.


Name a material which is used in making control rods in a nuclear reactor.


Write one balanced equation to show Emission of `beta^-` (i.e. a negative beta particle)


Two nuclei have mass numbers in the ratio 1: 2. What is the ratio of their nuclear densities?


The atomic mass of Uranium `""_92^238"U"` is 238.0508 u, while that of Thorium `""_90^234"Th"` is 234.0436u, and that of Helium `""_2^4"He"` "is 4.0026u. Alpha decay converts `""_92^238"U"` into `""_92^234"Th"` as, shown below:

`""_92^238"U" -> ( ""_90^234"Th" + ""_2^4"He" + "Energy" )`


\[\ce{^197_79Au}\] contains ______.


Nuclides with same neutron number N but different atomic number Z are called ______.


A nucleus of mass number A has a radius R such that ______.


A nucleus yYx emits one α and two β particles. The resulting nucleus is ______.


Two cars of mass m1 and m2 are moving in circles of radii r1 and r2, respectively. Their speeds are such that they make complete circles at the same time t. The ratio of their centripetal acceleration is:


Are the nucleons fundamental particles, or do they consist of still smaller parts? One way to find out is to probe a nucleon just as Rutherford probed an atom. What should be the kinetic energy of an electron for it to be able to probe a nucleon? Assume the diameter of a nucleon to be approximately 10–15 m.


Before the neutrino hypothesis, the beta decay process was throught to be the transition, `n -> p + vece`. If this was true, show that if the neutron was at rest, the proton and electron would emerge with fixed energies and calculate them. Experimentally, the electron energy was found to have a large range.


Mass numbers of two nuclei are in the ratio of 4 : 3. Their nuclear densities will be in the ratio of ______.


Which of the following are the constituents of the nucleus?


Assertion (R): Fusion of hydrogen nuclei into helium nuclei is the source of energy of all stars.

Reason (R): In fusion heavier nuclei split to form lighter nuclei.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×