Advertisements
Advertisements
प्रश्न
Multiply x2 + 4y2 + z2 + 2xy + xz – 2yz by (–z + x – 2y).
Advertisements
उत्तर
According to the question:
(x2 + 4y2 + z2 + 2xy + xz – 2yz) × (–z + x – 2y)
Now, multiply as follows:
= {x + (–2y) + (–z)}{(x)2 + (–2y)2 + (–z2) – (x)(–2y) – (–2y)(–z) – (–z)(x)}
= x3 + (–2y)3 + (–z)3 – 3 × x × (–2y) × (–z)
Use the identity:
(a + b + c)(a2 + b2 + c2 – ab – bc – ca) = a3 + b3 + c3 – 3abc
= x3 – 8y3 – z3 – 6xyz
APPEARS IN
संबंधित प्रश्न
Evaluate the following using suitable identity:
(998)3
If x + y + z = 0, show that x3 + y3 + z3 = 3xyz.
Simplify (2x + p - c)2 - (2x - p + c)2
If \[x^4 + \frac{1}{x^4} = 119\] , find the value of \[x^3 - \frac{1}{x^3}\]
Find the following product:
Find the following product:
Find the following product:
If \[x + \frac{1}{x} = 3\] then find the value of \[x^6 + \frac{1}{x^6}\].
If a2 - 5a - 1 = 0 and a ≠ 0 ; find:
- `a - 1/a`
- `a + 1/a`
- `a^2 - 1/a^2`
Evaluate: (9 − y) (7 + y)
Evaluate: `(4/7"a"+3/4"b")(4/7"a"-3/4"b")`
Expand the following:
(x - 3y - 2z)2
Simplify by using formula :
(5x - 9) (5x + 9)
If a - b = 10 and ab = 11; find a + b.
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a" + (1)/"a"`
If x + y + z = 12 and xy + yz + zx = 27; find x2 + y2 + z2.
If a2 + b2 + c2 = 41 and a + b + c = 9; find ab + bc + ca.
If `"p" + (1)/"p" = 6`; find : `"p"^4 + (1)/"p"^4`
Using suitable identity, evaluate the following:
1033
Simplify (2x – 5y)3 – (2x + 5y)3.
