Advertisements
Advertisements
प्रश्न
If `"p" + (1)/"p" = 6`; find : `"p"^4 + (1)/"p"^4`
Advertisements
उत्तर
`("p"^2 + 1/"p"^2)`
= `"p"^4 + (1)/"p"^4 + 2`
⇒ (34)2 = `"p"^4 + (1)/"p"^4 + 2`
⇒ `"p"^4 + (1)/"p"^4`
= 1158 - 2
= 1154.
APPEARS IN
संबंधित प्रश्न
Find the following product:
(7p4 + q) (49p8 − 7p4q + q2)
If \[x^3 + \frac{1}{x^3} = 110\], then \[x + \frac{1}{x} =\]
75 × 75 + 2 × 75 × 25 + 25 × 25 is equal to
\[\frac{( a^2 - b^2 )^3 + ( b^2 - c^2 )^3 + ( c^2 - a^2 )^3}{(a - b )^3 + (b - c )^3 + (c - a )^3} =\]
Use the direct method to evaluate :
(0.5−2a) (0.5+2a)
Evaluate: (2 − z) (15 − z)
Simplify by using formula :
(x + y - 3) (x + y + 3)
Evaluate the following without multiplying:
(103)2
If p2 + q2 + r2 = 82 and pq + qr + pr = 18; find p + q + r.
Without actually calculating the cubes, find the value of:
`(1/2)^3 + (1/3)^3 - (5/6)^3`
