Advertisements
Advertisements
प्रश्न
If \[x^3 + \frac{1}{x^3} = 110\], then \[x + \frac{1}{x} =\]
पर्याय
5
10
15
none of these
Advertisements
उत्तर
In the given problem, we have to find the value of `x + 1/x`
Given `x^3 + 1/x^3 = 110`
We shall use the identity `(a + b)^3 = a^3 + b^3 + 3ab (a+b)`
`(x+1/x)^3 = x^3 + 1/x^3 + 3 xx x xx 1/x(x+ 1/x)`
`(x+1/x)^3 = x^3 + 1/x^3 + 3 (x+ 1/x)`
Put `x + 1/x = y`we get,
`(y)^3 = x^3 + 1/x^3 + 3 (y)`
Substitute y = 5 in the above equation we get
`(5)^3 = x^3 + 1/x^3 + 3(5)`
`125 = x^3 + 1/x^3 + 15`
`125 - 15 = x^3 + 1/x^3`
`110 = x^3 + 1/x^3`
The Equation `(y)^3 = x^3 + 1/x^3 + 3(y)` satisfy the condition that `x^3 + 1/x^3 = 110`
Hence the value of `x+ 1/x` is 5.
APPEARS IN
संबंधित प्रश्न
Evaluate the following product without multiplying directly:
103 × 107
Evaluate the following product without multiplying directly:
95 × 96
Factorise the following:
64a3 – 27b3 – 144a2b + 108ab2
if `x^2 + 1/x^2 = 79` Find the value of `x + 1/x`
Simplify the following product:
(x2 + x − 2)(x2 − x + 2)
Write the expanded form:
`(-3x + y + z)^2`
If \[x - \frac{1}{x} = 7\], find the value of \[x^3 - \frac{1}{x^3}\].
Find the following product:
(3x + 2y) (9x2 − 6xy + 4y2)
Find the following product:
Use identities to evaluate : (998)2
Evaluate : (4a +3b)2 - (4a - 3b)2 + 48ab.
If a + `1/a`= 6 and a ≠ 0 find :
(i) `a - 1/a (ii) a^2 - 1/a^2`
The number x is 2 more than the number y. If the sum of the squares of x and y is 34, then find the product of x and y.
If 3x + 4y = 16 and xy = 4, find the value of 9x2 + 16y2.
Use the direct method to evaluate the following products:
(5a + 16) (3a – 7)
Use the direct method to evaluate :
(2a+3) (2a−3)
Expand the following:
(x - 5) (x - 4)
Evaluate the following without multiplying:
(1005)2
If `"a" + 1/"a" = 6;`find `"a"^2 - 1/"a"^2`
Simplify (2x – 5y)3 – (2x + 5y)3.
