Advertisements
Advertisements
प्रश्न
If \[x^3 + \frac{1}{x^3} = 110\], then \[x + \frac{1}{x} =\]
पर्याय
5
10
15
none of these
Advertisements
उत्तर
In the given problem, we have to find the value of `x + 1/x`
Given `x^3 + 1/x^3 = 110`
We shall use the identity `(a + b)^3 = a^3 + b^3 + 3ab (a+b)`
`(x+1/x)^3 = x^3 + 1/x^3 + 3 xx x xx 1/x(x+ 1/x)`
`(x+1/x)^3 = x^3 + 1/x^3 + 3 (x+ 1/x)`
Put `x + 1/x = y`we get,
`(y)^3 = x^3 + 1/x^3 + 3 (y)`
Substitute y = 5 in the above equation we get
`(5)^3 = x^3 + 1/x^3 + 3(5)`
`125 = x^3 + 1/x^3 + 15`
`125 - 15 = x^3 + 1/x^3`
`110 = x^3 + 1/x^3`
The Equation `(y)^3 = x^3 + 1/x^3 + 3(y)` satisfy the condition that `x^3 + 1/x^3 = 110`
Hence the value of `x+ 1/x` is 5.
APPEARS IN
संबंधित प्रश्न
Expand the following, using suitable identity:
(–2x + 5y – 3z)2
Write the following cube in expanded form:
(2a – 3b)3
Find the cube of the following binomials expression :
\[2x + \frac{3}{x}\]
If \[x - \frac{1}{x} = 5\], find the value of \[x^3 - \frac{1}{x^3}\]
Find the following product:
Find the following product:
(2ab − 3b − 2c) (4a2 + 9b2 +4c2 + 6 ab − 6 bc + 4ca)
If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]
Use identities to evaluate : (998)2
Use the direct method to evaluate :
(xy+4) (xy−4)
Evaluate: (9 − y) (7 + y)
Find the squares of the following:
3p - 4q2
Evaluate the following without multiplying:
(999)2
If m - n = 0.9 and mn = 0.36, find:
m + n
If x + y = 1 and xy = -12; find:
x2 - y2.
If `"a"^2 - 7"a" + 1` = 0 and a = ≠ 0, find :
`"a" + (1)/"a"`
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a" - (1)/"a"`
Simplify:
(3a + 2b - c)(9a2 + 4b2 + c2 - 6ab + 2bc +3ca)
Evaluate the following :
7.16 x 7.16 + 2.16 x 7.16 + 2.16 x 2.16
Factorise the following:
4x2 + 20x + 25
