Advertisements
Advertisements
प्रश्न
Find the following product:
Advertisements
उत्तर
Given (1 + x) (1 − x + x2)
We shall use the identity `(a+b)(a^2 - ab +b^2) = a^3 + b^3`
We can rearrange the (1 + x) (1 − x + x2)as
` = (1+x)[(1)^2 - (1)(x)+(x)^2]`
` = (1)^3 + (x)^3`
` = (1)xx (1)xx(1) + (x)xx (x)xx(x)`
` = 1+x^3`
Hence the Product value of `(1+x)(1-x+x^2)`is `1+x^2`
APPEARS IN
संबंधित प्रश्न
Evaluate the following product without multiplying directly:
103 × 107
Evaluate the following product without multiplying directly:
95 × 96
Evaluate the following using suitable identity:
(99)3
Factorise the following:
8a3 – b3 – 12a2b + 6ab2
Evaluate the following using identities:
`(2x+ 1/x)^2`
Evaluate the following using identities:
`(a^2b - b^2a)^2`
Evaluate of the following:
`(10.4)^3`
Find the value of 64x3 − 125z3, if 4x − 5z = 16 and xz = 12.
Find the following product:
\[\left( \frac{x}{2} + 2y \right) \left( \frac{x^2}{4} - xy + 4 y^2 \right)\]
Evaluate:
483 − 303 − 183
Mark the correct alternative in each of the following:
If \[x + \frac{1}{x} = 5\] then \[x^2 + \frac{1}{x^2} = \]
If a + b + c = 9 and ab + bc + ca = 23, then a2 + b2 + c2 =
Find the square of 2a + b.
Evaluate: (2a + 0.5) (7a − 0.3)
Expand the following:
(a + 4) (a + 7)
Expand the following:
(a + 3b)2
Evaluate, using (a + b)(a - b)= a2 - b2.
399 x 401
If a - b = 10 and ab = 11; find a + b.
If `x + (1)/x = 3`; find `x^2 + (1)/x^2`
If a2 + b2 + c2 = 41 and a + b + c = 9; find ab + bc + ca.
