Advertisements
Advertisements
प्रश्न
If x = 3 and y = − 1, find the values of the following using in identify:
\[\left( \frac{5}{x} + 5x \right)\] \[\left( \frac{25}{x^2} - 25 + 25 x^2 \right)\]
Advertisements
उत्तर
In the given problem, we have to find the value of equation using identity
Given \[\left( \frac{5}{x} + 5x \right)\] \[\left( \frac{25}{x^2} - 25 + 25 x^2 \right)\]
We shall use the identity, `a^3 + b^3 = (a+ b) (a^2 - ab + b^2)`
We can rearrange the \[\left( \frac{5}{x} + 5x \right)\] \[\left( \frac{25}{x^2} - 25 + 25 x^2 \right)\]as
`= (5/x + 5x)[(5/x)^2 + (5x)^2 - (5/x)(5x)]`
` =(5/x)^3 + (5x)^3 `
` = (5/x) xx (5/x) xx (5/x) + (5x)xx (5x)xx(5x)`
` = 125/x^3 + 125x^3`
Now substituting the value x = 3 in `125/x^3 + 125x^3`
`= 125/x^3 + 125x^3`
`= 125/3^3 + 125 xx 3^3`
`= 125/27 + 125 xx 27`
`= 125/27 + 3375`
Taking Least common multiple, we get
` = 125 / 27 + (3375 xx 27)/(1xx 27)`
`= 125/27 + 91125/27`
` = (125 + 91125)/27`
` = 91250/27`
Hence the Product value of \[\left( \frac{5}{x} + 5x \right)\] \[\left( \frac{25}{x^2} - 25 + 25 x^2 \right)\] is ` = 91250/27`.
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
(3 – 2x) (3 + 2x)
Evaluate the following product without multiplying directly:
95 × 96
Factorise:
4x2 + 9y2 + 16z2 + 12xy – 24yz – 16xz
If `x^2 + 1/x^2 = 66`, find the value of `x - 1/x`
Simplify the following expressions:
`(x^2 - x + 1)^2 - (x^2 + x + 1)^2`
Find the following product:
If x = 3 and y = − 1, find the values of the following using in identify:
\[\left( \frac{x}{y} - \frac{y}{3} \right) \frac{x^2}{16} + \frac{xy}{12} + \frac{y^2}{9}\]
Evaluate:
483 − 303 − 183
If \[\frac{a}{b} + \frac{b}{a} = - 1\] then a3 − b3 =
Use the direct method to evaluate the following products:
(a – 8) (a + 2)
Evaluate: `(2"a"+1/"2a")(2"a"-1/"2a")`
If `"a" - 1/"a" = 10`; find `"a"^2 - 1/"a"^2`
If p + q = 8 and p - q = 4, find:
pq
If 2x + 3y = 10 and xy = 5; find the value of 4x2 + 9y2
If `"a"^2 + (1)/"a"^2 = 14`; find the value of `"a" + (1)/"a"`
If `"r" - (1)/"r" = 4`; find: `"r"^2 + (1)/"r"^2`
Simplify:
(3x + 5y + 2z)(3x - 5y + 2z)
If a + b + c = 0, then a3 + b3 + c3 is equal to ______.
Without actually calculating the cubes, find the value of:
(0.2)3 – (0.3)3 + (0.1)3
