Advertisements
Advertisements
प्रश्न
Multiply the following:
(3x2 + 4x – 8), (2x2 – 4x + 3)
Advertisements
उत्तर
We have,
(3x2 + 4x – 8) and (2x2 – 4x + 3)
∴ (3x2 + 4x – 8)(2x2 – 4x + 3) = 3x2(2x2 – 4x + 3) + 4x(2x2 – 4x + 3) – 8(2x2 – 4x + 3)
= 6x4 – 12x3 + 9x2 + 8x3 – 16x2 + 12x – 16x2 + 32x – 24
= 6x4 – 12x3 + 8x3 + 9x2 – 16x2 – 16x2 + 12x + 32x – 24 ...[Grouping like terms]
= 6x4 – 4x3 – 23x2 + 44x – 24
APPEARS IN
संबंधित प्रश्न
Simplify the following using the identities: \[\frac{{58}^2 - {42}^2}{16}\]
Simplify the following using the identities: 1.73 × 1.73 − 0.27 × 0.27
Find the following product: (3x + 5) (3x + 11)
Find the following product: (3x − 4y) (2x − 4y)
Evaluate the following: 102 × 106
Simplify:
(3x + 2y)2 + (3x – 2y)2
Simplify:
(1.5p + 1.2q)2 – (1.5p – 1.2q)2
Simplify:
(b2 – 49)(b + 7) + 343
Using suitable identities, evaluate the following.
(103)2
Carry out the following division:
17ab2c3 ÷ (–abc2)
