Advertisements
Advertisements
प्रश्न
Multiply the following:
(3x2 + 4x – 8), (2x2 – 4x + 3)
Advertisements
उत्तर
We have,
(3x2 + 4x – 8) and (2x2 – 4x + 3)
∴ (3x2 + 4x – 8)(2x2 – 4x + 3) = 3x2(2x2 – 4x + 3) + 4x(2x2 – 4x + 3) – 8(2x2 – 4x + 3)
= 6x4 – 12x3 + 9x2 + 8x3 – 16x2 + 12x – 16x2 + 32x – 24
= 6x4 – 12x3 + 8x3 + 9x2 – 16x2 – 16x2 + 12x + 32x – 24 ...[Grouping like terms]
= 6x4 – 4x3 – 23x2 + 44x – 24
APPEARS IN
संबंधित प्रश्न
Simplify the following using the formula: (a − b)(a + b) = a2 − b2: 113 × 87
Find the value of x, if 5x = (50)2 − (40)2.
Find the following product: (3x2 − 4xy) (3x2 − 3xy)
Expand the following:
(2x + 3y + 4z)2
Using algebraic identity, find the coefficients of x2, x and constant term without actual expansion
(x + 5)(x + 6)(x + 7)
Simplify:
(3x + 2y)2 – (3x – 2y)2
Simplify:
(1.5p + 1.2q)2 – (1.5p – 1.2q)2
Simplify:
(x2 – 4) + (x2 + 4) + 16
Expand the following, using suitable identities.
`((2a)/3 + b/3)((2a)/3 - b/3)`
Using suitable identities, evaluate the following.
52 × 53
