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प्रश्न
Expand the following, using suitable identities.
(x2y – xy2)2
बेरीज
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उत्तर
We have,
(x2y – xy2)2 = (x2y)2 + (xy2)2 – 2x2y × xy2 ...[Using the identity, (a – b)2 = a2 + b2 – 2ab]
= x4y2 + x2y4 – 2x3y3
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पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३२]
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