Advertisements
Advertisements
प्रश्न
Multiply the following:
(3x2 + 4x – 8), (2x2 – 4x + 3)
Advertisements
उत्तर
We have,
(3x2 + 4x – 8) and (2x2 – 4x + 3)
∴ (3x2 + 4x – 8)(2x2 – 4x + 3) = 3x2(2x2 – 4x + 3) + 4x(2x2 – 4x + 3) – 8(2x2 – 4x + 3)
= 6x4 – 12x3 + 9x2 + 8x3 – 16x2 + 12x – 16x2 + 32x – 24
= 6x4 – 12x3 + 8x3 + 9x2 – 16x2 – 16x2 + 12x + 32x – 24 ...[Grouping like terms]
= 6x4 – 4x3 – 23x2 + 44x – 24
APPEARS IN
संबंधित प्रश्न
Find the following product: \[\left( y^2 + \frac{5}{7} \right)\left( y^2 - \frac{14}{5} \right)\]
Evaluate the following: 103 × 96
Expand the following:
(3a + 1) (3a – 2) (3a + 4)
Evaluate the following by using identities:
983
Multiply the following:
(2x – 2y – 3), (x + y + 5)
Simplify:
`(7/9 a + 9/7 b)^2 - ab`
Expand the following, using suitable identities.
(xy + yz)2
Expand the following, using suitable identities.
`(4/5p + 5/3q)^2`
Expand the following, using suitable identities.
(x2 + y2)(x2 – y2)
Using suitable identities, evaluate the following.
(49)2
