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प्रश्न
Monochromatic light of frequency 6.0 × 1014 Hz is produced by a laser. The power emitted is 2.0 × 10−3 W. Estimate the number of photons emitted per second on an average by the source
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उत्तर
Energy = hν
On putting the values, we get:
number of photons * energy of one photon = total energy
number of photons=`(2xx10^-3)/(6.63xx10^-34xx6xx10^14)`
=`5 xx 10^15` photons
संबंधित प्रश्न
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(a) \[z = \frac{\lambda D}{2d}\]
(b) \[\frac{\lambda D}{d}\]
(c) \[\frac{\lambda D}{4d}\]
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