मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Match the polymers given in Column I with their repeating units given in Column II. Column I Column II (i) Acrilan (a) −(CHX2−CH)−n....|.......CX6HX5 (ii) Polystyrene (b) Cl.......|........−(CHX2−C= - Chemistry

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प्रश्न

Match the polymers given in Column I with their repeating units given in Column II.

Column I Column II
(i) Acrilan

(a) \[\begin{array}{cc}
\ce{-(CH2 - CH)\underset{n}{-}}\\
\phantom{....}|\\
\phantom{.......}\ce{C6H5}
\end{array}\]

(ii) Polystyrene (b) \[\begin{array}{cc}
\ce{Cl}\phantom{.......}\\
|\phantom{........}\\
\phantom{}\ce{-(CH2 - C = CH - CH2)\underset{n}{-}}
\end{array}\]
(iii) Neoprene (c) \[\begin{array}{cc}
\phantom{................................}\ce{CN}\\
\phantom{..............................}|\\
\ce{-(CH2 - CH = CH - CH2 - CH2 - CH)\underset{n}{-}}
\end{array}\]
(iv) Novolac (d) \[\begin{array}{cc}
\ce{-(CH2 - CH)\underset{n}{-}}\\
\phantom{.....}|\\
\phantom{.......}\ce{CN}
\end{array}\]
(v) Buna—N (e) 
  (f)  \[\begin{array}{cc}
\ce{-(CH2 - CH)\underset{n}{-}}\\
\phantom{.....}|\\
\phantom{......}\ce{Cl}
\end{array}\]
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उत्तर

Column I Column II
(i) Acrilan

(d) \[\begin{array}{cc}
\ce{-(CH2 - CH)\underset{n}{-}}\\
\phantom{.....}|\\
\phantom{.......}\ce{CN}
\end{array}\]

(ii) Polystyrene (a) \[\begin{array}{cc}
\ce{-(CH2 - CH)\underset{n}{-}}\\
\phantom{....}|\\
\phantom{.......}\ce{C6H5}
\end{array}\]
(iii) Neoprene (b) \[\begin{array}{cc}
\ce{Cl}\phantom{.......}\\
|\phantom{........}\\
\phantom{}\ce{-(CH2 - C = CH - CH2)\underset{n}{-}}
\end{array}\]
(iv) Novolac (e)  
(v) Buna—N (c) \[\begin{array}{cc}
\phantom{................................}\ce{CN}\\
\phantom{..............................}|\\
\ce{-(CH2 - CH = CH - CH2 - CH2 - CH)\underset{n}{-}}
\end{array}\]
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पाठ 15: Polymers - Multiple Choice Questions (Type - I) [पृष्ठ २२४]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
पाठ 15 Polymers
Multiple Choice Questions (Type - I) | Q 45 | पृष्ठ २२४

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\[\begin{array}{cc}
\phantom{....}\ce{O}\phantom{............}\ce{O}\phantom{...................}\ce{H}\phantom{.....}\\
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