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प्रश्न
`\lim_{x \to 0} \frac{e^\tan x - 1}{\tan x}`
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उत्तर
`\lim_{x \to 0} \left[ \frac{e^\tan x - 1}{\tan x} \right]`
If x → 0, then tan x → 0.
Let y = tan x
\[{= \lim}_{y \to 0} \left[ \frac{e^y - 1}{y} \right]\]
\[ = 1\]
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