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प्रश्न
It has been observed that first ionization energy of 5 d series of transition elements are higher than that of 3d and 4d series, explain why?
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उत्तर
The transition elements of 5d series have intervening 4f orbitals. There is greater effective nuclear charge acting on outer valence electrons due to the weak shielding by 4f electrons. Hence first ionisation energy of 5d series of transition elements are higher than that of 3d and 4d series.
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संबंधित प्रश्न
ln which pair highest oxidation states of transition metals are found:
What are the transition elements? Write two characteristics of the transition elements.
Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?
Following are the transition metal ions of 3d series:
Ti4+, V2+, Mn3+, Cr3+
(Atomic numbers: Ti = 22, V = 23, Mn = 25, Cr = 24)
Answer the following:
1) Which ion is most stable in an aqueous solution and why?
2) Which ion is a strong oxidising agent and why?
3) Which ion is colourless and why?
Write balanced chemical equations for the conversion of `CrO_4^(2-)` to `Cr_2O_7^(2-)` in acidic medium and `Cr_2O_7^(2-)` to `CrO_4^(2-)`
in basic medium.
Give reasons: Sc3+ is colourless in aqueous solution whereas Ti3+ is coloured.
Ionisation enthalpies of Ce, Pr and Nd are higher than Th, Pa and U. Why?
The disproportionation of \[\ce{MnO^{2-}_4}\] in acidic medium resulted in the formation of two manganese compounds A and B. If the oxidation state of Mn in B is smaller than that of A, then the spin-only magnetic moment (µ) value of B in BM is ______. (Nearest integer)
Write the number of unpaired electrons in Cr3+.
(Atomic number of Cr = 24)
The compounds of \[\ce{Ti^4+}\] ions are colourless due to ______.
