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संबंधित प्रश्न
A half metre rod is pivoted at the centre with two weights of 20gf and 12gf suspended at a perpendicular distance of 6 cm and 10 cm from the pivot respectively as shown below.
1) Which of the two forces acting on the rigid rod causes clockwise moment?
2) Is the rod in equilibrium?
3) The direction of 20 kgf force is reversed. What is the magnitude of the resultant moment of the forces on the rod?
A body X of mass 5 kg is moving with velocity 20 m s-2 while another body Y of mass 20 kg is moving with velocity 5 m S-1. Compare the momentum of the two bodies.
State two factor on which moment of force about a point depends.
State one way to reduce the moment of given force about a given axis of rotation.
A body is acted upon by two forces of magnitude F but in opposite directions. State the effect of the force if both forces act at the same point of the body.
A wheel of diameter 2 m is shown in the figure with the axle at O. A force F = 2 N is applied at B in the direction shown in the figure. Calculate the moment of force about
- the centre O, and
- the point A.
A uniform metre rule of weight 10gf is pivoted at its 0 mark.
What moment of force depresses the rule?
A meter scale is provided at 10 cm mark and is balanced by suspending 400 g from 0 cm mark (fig.). Calculate the mass of meter scale.
The perpendicular distance between the point of application of force and turning point is 1.75 m when a force of 80 N acts on a rigid body. Calculate the moment of force.
On a see-saw, two children of masses 30 kg and 50 kg are sitting on one side of it at distance 2 m and 2.5 m respectively, from its middle, where should a man of mass 74 kg sit to balance it?
