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प्रश्न
In which chemical reaction does carbon exhibit variation of oxidation state from - 4 to + 4? Write a balanced chemical reaction.
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उत्तर
In the combustion of methane, carbon exhibits variation from – 4 to + 4. The reaction is as follows:
\[\ce{CH4 + 2O2->CO2 + 2H2O}\]
In CH4, the oxidation state of carbon is – 4 while in CO2, the oxidation state of carbon is + 4.
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संबंधित प्रश्न
Choose the correct option.
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Choose the correct option.
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H3PO3
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Identify the following pair of species is in its oxidized state?
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Identify the following pair of species is in its oxidized state?
\[\ce{O2/O^2-}\]
Identify the following pair of species is in its oxidized state?
Cl2/Cl−
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Complete the following table:
Assign oxidation number to the underlined species and write Stock notation of compound
| Compound | Oxidation number | Stock notation |
| AuCl3 | ||
| SnCl2 | ||
| \[\ce{\underline{{V}}_2O^{4-}_{7}}\] | ||
| \[\ce{\underline{{Pt}}Cl^2-_6}\] | ||
| H3AsO3 |
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| Compound | Oxidation no. of underlined element |
| i. \[\ce{\underline{C}_4H4O^{2-}_6}\] | a. +2.5 |
| ii. \[\ce{\underline{N}_3H}\] | b. +1.5 |
| iii. \[\ce{Mg2\underline{P}_2O7}\] | c. +5 |
| iv. \[\ce{Na2\underline{S}_4O6}\] | d. `-1//3` |
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\[\ce{2Ag+ + Cu -> 2Ag + Cu^2+}\]
