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Calculate the oxidation number of the underlined atom. H2S4O6 - Chemistry

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प्रश्न

Calculate the oxidation number of the underlined atom.

H2S4O6

संख्यात्मक
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उत्तर

H2S4O6

Oxidation number of H = +1

Oxidation number of O = –2

H2S4O6 is a neutral molecule.

∴ Sum of the oxidation numbers of all atoms = 0

∴ 2 × (Oxidation number of H) + 4 × (Oxidation number of S) + 6 × (Oxidation number of O) = 0

∴ 2 × (+1) + 4 × (Oxidation number of S) + 6 × (–2) = 0

∴ 4 × (Oxidation number of S) + 2 – 12 = 0

∴ 4 × (Oxidation number of S) = + 10 

∴ Oxidation number of S =`+10/4`

∴ Oxidation number of S in H2S4O6 = +2.5

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Oxidation Number
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पाठ 6: Redox Reactions - Exercises [पृष्ठ ९२]

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बालभारती Chemistry [English] Standard 11 Maharashtra State Board
पाठ 6 Redox Reactions
Exercises | Q 3. (C)(e) | पृष्ठ ९२

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