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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Calculate the oxidation number of the underlined atom. H2S4O6

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प्रश्न

Calculate the oxidation number of the underlined atom.

H2S4O6

संख्यात्मक
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उत्तर

H2S4O6

Oxidation number of H = +1

Oxidation number of O = –2

H2S4O6 is a neutral molecule.

∴ Sum of the oxidation numbers of all atoms = 0

∴ 2 × (Oxidation number of H) + 4 × (Oxidation number of S) + 6 × (Oxidation number of O) = 0

∴ 2 × (+1) + 4 × (Oxidation number of S) + 6 × (–2) = 0

∴ 4 × (Oxidation number of S) + 2 – 12 = 0

∴ 4 × (Oxidation number of S) = + 10 

∴ Oxidation number of S =`+10/4`

∴ Oxidation number of S in H2S4O6 = +2.5

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पाठ 6: Redox Reactions - Exercises [पृष्ठ ९२]

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बालभारती Chemistry [English] Standard 11 Maharashtra State Board
पाठ 6 Redox Reactions
Exercises | Q 3. (C)(e) | पृष्ठ ९२

संबंधित प्रश्‍न

Choose the correct option.

Oxidation number of carbon in H2CO3 is


Calculate the oxidation number of the underlined atom.

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Calculate the oxidation number of the underlined atom.

HNO3


What is oxidation?


Identify the following pair of species is in its oxidized state?

Cu/Cu2+


Identify the following pair of species is in its oxidized state?

\[\ce{O2/O^2-}\]


Provide the stock notation for the following compound:

MnO


Provide the stock notation for the following compound:

CuO


Assign oxidation number atom in the following species.

Na2S2O3


Assign oxidation number atom in the following species.

H3BO3


Which of the following redox couple is a stronger oxidizing agent?

\[\ce{MnO^Θ_4}\](E0 = 1.51 V) and \[\ce{Cr2O^{2Θ}_7}\](E0 = 1.33 V)


Which of the following redox couple is a stronger reducing agent?

Zn (E0 = - 0.76 V) and Fe (E0 = - 0.44 V)


Oxidation state of Xe in XeOF4 is ____________.


In the reaction,

\[\ce{MnO^{-1}_4 (aq) + Br^{-1}(aq) -> MnO2(s) + BrO^{-1}_3(aq)}\]

the correct change in oxidation number of the species involved is ______.


Which of the following is NOT an example of redox reaction?


Identify the strongest oxidising agent.

\[\ce{Na^+ + e^- -> Na}\]; E0 = −2.714 V

\[\ce{Pt^{2+} + 2e^- -> Pt}\]; E0 = +1.200 V

\[\ce{I2 + 2e^- -> 2I^-}\]; E0 = + 0.535 V

\[\ce{Co^{2+} + 2e^- -> Co}\]; 0 = −0.280 V


Match the following.

Compound Oxidation no. of underlined element
i. \[\ce{\underline{C}_4H4O^{2-}_6}\] a. +2.5
ii. \[\ce{\underline{N}_3H}\] b. +1.5
iii. \[\ce{Mg2\underline{P}_2O7}\] c. +5
iv. \[\ce{Na2\underline{S}_4O6}\] d. `-1//3`

All of these are CORRECT for the complex K4[Mn(CN)6], EXCEPT:


In which among the following compounds, oxidation number of nitrogen is + 5?


When methane undergoes combustion in air, the oxidation number of C ____________.


What is the oxidation number of Carbon in K2C2O4?


Carbon is present in highest oxidation number in ______.


What is the oxidation state of chlorine atom in perchloric acid?


Among group 16 elements, which one does not show −2 oxidation state?


In which of the compounds does ‘manganese’ exhibit the highest oxidation number?


Which of the following changes exhibit that nitrogen undergoes oxidation?


Which of the following statements are INCORRECT?

  1. All the transition metals except scandium form MO oxides which are ionic.
  2. The highest oxidation number corresponding to the group number in transition metals oxides is attained in Sc2B5 to Mn2B7.
  3. Basic character increases from V2B5 to V2B4 to V2B5.
  4. V2B4 dissolves in acids to give VO43– salts.
  5. CrO is basic but Cr2B5 is atmospheric.

Choose the correct answer from the options given below:


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