मराठी

In Triangle Abc, Prove the Following: B Cos B + C Cos C = a Cos ( B − C )

Advertisements
Advertisements

प्रश्न

In triangle ABC, prove the following: 

\[b \cos B + c \cos C = a \cos \left( B - C \right)\]

 

Advertisements

उत्तर

Let 

\[\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = k\] 

Then, 

Consider the LHS of the equation \[b \cos B + c \cos C = a \cos \left( B - C \right)\]

\[LHS = b\cos B + c\cos C\]
\[ = k\left( \sin B\cos B + \sin C\cos C \right) \]
\[ = \frac{k}{2}\left( 2sinBcosB + 2sinCcosC \right)\]
\[ = \frac{k}{2}\left( \sin2B + \sin2C \right) . . . \left( 1 \right)\]
\[ RHS = a\cos\left( B - C \right)\]
\[ = k\sin A\cos\left( B - C \right) \]
\[ = \frac{k}{2}\left[ 2\sin A\cos\left( B - C \right) \right]\]
\[ = \frac{k}{2}\left[ \sin\left( A + B - C \right) + \sin\left( A - B + C \right) \right] \left[ \because 2\sin A\cos B = \sin\left( A + B \right) + \sin\left( A - B \right) \right]\]
\[ = \frac{k}{2}\left[ \sin\left( \pi - C - C \right) + \sin\left( \pi - B - B \right) \right] \left[ \because \sin\left( \pi - A \right) = \sin A, A + B + C = \pi \right]\]
\[ = \frac{k}{2}\left( \sin2C + \sin2B \right)\]
\[ = \frac{k}{2}\left( \sin2B + \sin2C \right) = LHS \left[ from\left( 1 \right) \right]\]
\[\text{ Hence proved } .\]

shaalaa.com
Sine and Cosine Formulae and Their Applications
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

संबंधित प्रश्‍न

If in ∆ABC, ∠A = 45°, ∠B = 60° and ∠C = 75°, find the ratio of its sides. 


In any triangle ABC, prove the following: 

\[\sin \left( \frac{B - C}{2} \right) = \frac{b - c}{a} \cos\frac{A}{2}\]

 


In triangle ABC, prove the following: 

\[\frac{a^2 - c^2}{b^2} = \frac{\sin \left( A - C \right)}{\sin \left( A + C \right)}\] 


In triangle ABC, prove the following: 

\[a \left( \sin B - \sin C \right) + \left( \sin C - \sin A \right) + c \left( \sin A - \sin B \right) = 0\]

 


In triangle ABC, prove the following: 

\[\frac{a^2 \sin \left( B - C \right)}{\sin A} + \frac{b^2 \sin \left( C - A \right)}{\sin B} + \frac{c^2 \sin \left( A - B \right)}{\sin C} = 0\]

 


In triangle ABC, prove the following: 

\[a^2 \left( \cos^2 B - \cos^2 C \right) + b^2 \left( \cos^2 C - \cos^2 A \right) + c^2 \left( \cos^2 A - \cos^2 B \right) = 0\]

 


In triangle ABC, prove the following: 

\[\frac{\cos^2 B - \cos^2 C}{b + c} + \frac{\cos^2 C - \cos^2 A}{c + a} + \frac{co s^2 A - \cos^2 B}{a + b} = 0\]

 


In ∆ABC, prove that: \[\frac{b \sec B + c \sec C}{\tan B + \tan C} = \frac{c \sec C + a \sec A}{\tan C + \tan A} = \frac{a \sec A + b \sec B}{\tan A + \tan B}\]


In ∆ABC, prove that if θ be any angle, then b cosθ = c cos (A − θ) + a cos (C + θ). 


At the foot of a mountain, the elevation of it summit is 45°; after ascending 1000 m towards the mountain up a slope of 30° inclination, the elevation is found to be 60°. Find the height of the mountain. 


If the sides ab and c of ∆ABC are in H.P., prove that \[\sin^2 \frac{A}{2}, \sin^2 \frac{B}{2} \text{ and } \sin^2 \frac{C}{2}\]


In \[∆ ABC, if a = \sqrt{2}, b = \sqrt{3} \text{ and } c = \sqrt{5}\] show that its area is \[\frac{1}{2}\sqrt{6} sq .\] units.


In ∆ABC, prove the following: \[b \left( c \cos A - a \cos C \right) = c^2 - a^2\]


In ∆ABC, prove the following

\[\left( c^2 - a^2 + b^2 \right) \tan A = \left( a^2 - b^2 + c^2 \right) \tan B = \left( b^2 - c^2 + a^2 \right) \tan C\] 

 


In ∆ABC, prove the following:

\[\frac{c - b \cos A}{b - c \cos A} = \frac{\cos B}{\cos C}\] 

 


In ∆ABC, prove that  \[a \left( \cos B + \cos C - 1 \right) + b \left( \cos C + \cos A - 1 \right) + c\left( \cos A + \cos B - 1 \right) = 0\]


a cos + b cos B + c cos C = 2sin sin 


In ∆ABC, prove the following: 

\[a^2 = \left( b + c \right)^2 - 4 bc \cos^2 \frac{A}{2}\]


In ∆ABC, prove the following:

\[4\left( bc \cos^2 \frac{A}{2} + ca \cos^2 \frac{B}{2} + ab \cos^2 \frac{C}{2} \right) = \left( a + b + c \right)^2\]


In ∆ABC, prove the following: 

\[\sin^3 A \cos \left( B - C \right) + \sin^3 B \cos \left( C - A \right) + \sin^3 C \cos \left( A - B \right) = 3 \sin A \sin B \sin C\]


If in \[∆ ABC, \cos^2 A + \cos^2 B + \cos^2 C = 1\] prove that the triangle is right-angled. 

 


In \[∆ ABC \text{ if } \cos C = \frac{\sin A}{2 \sin B}\] prove that the triangle is isosceles.  


Answer  the following questions in one word or one sentence or as per exact requirement of the question. 

Find the area of the triangle ∆ABC in which a = 1, b = 2 and \[\angle C = 60º\] 



Answer  the following questions in one word or one sentence or as per exact requirement of the question. 

In a ∆ABC, if b = 20, c = 21 and \[\sin A = \frac{3}{5}\] 

 


Answer the following questions in one word or one sentence or as per exact requirement of the question.  

In ∆ABC, if a = 8, b = 10, c = 12 and C = λA, find the value of λ


Answer the following questions in one word or one sentence or as per exact requirement of the question. 

If the sides of a triangle are proportional to 2, \[\sqrt{6}\] and \[\sqrt{3} - 1\] find the measure of its greatest angle. 


Answer the following questions in one word or one sentence or as per exact requirement of the question.  

If in a ∆ABC, \[\frac{\cos A}{a} = \frac{\cos B}{b} = \frac{\cos C}{c}\] then find the measures of angles ABC


Mark the correct alternative in each of the following:
In any ∆ABC, \[\sum^{}_{} a^2 \left( \sin B - \sin C \right)\] = 


Mark the correct alternative in each of the following: 

In a ∆ABC, if a = 2, \[\angle B = 60°\]  and\[\angle C = 75°\] 

 


Mark the correct alternative in each of the following: 

In any ∆ABC, 2(bc cosA + ca cosB + ab cosC) = 


Mark the correct alternative in each of the following: 

In a ∆ABC, if  \[\left( c + a + b \right)\left( a + b - c \right) = ab\] then the measure of angle C is 


Find the value of `(1 + cos  pi/8)(1 + cos  (3pi)/8)(1 + cos  (5pi)/8)(1 + cos  (7pi)/8)`


If x cos θ = `y cos (theta + (2pi)/3) = z cos (theta + (4pi)/3)`, then find the value of xy + yz + zx.


If x = sec Φ – tan Φ and y = cosec Φ + cot Φ then show that xy + x – y + 1 = 0
[Hint: Find xy + 1 and then show that x – y = –(xy + 1)]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×