मराठी

In the given figure, ΔOAB ~ ΔOCD. If AB = 8 cm, BO = 6.4 cm, OC = 3.5 cm and CD = 5 cm, find (i) OA (ii) DO.

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प्रश्न

In the given figure, ΔOAB ~ ΔOCD. If AB = 8 cm, BO = 6.4 cm, OC = 3.5 cm and CD = 5 cm, find (i) OA (ii) DO.

बेरीज
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उत्तर

(i) Let OA be X cm.
∵ Δ OAB - Δ OCD 

∴`(OA)/(OC)=(AB)/(CD)`                                   

⇒ `x/3.5=8/5` 

⇒`x=(8xx3.5)/5=5.6`  

Hence, OA = 5.6 cm  

(ii) Let DO be Y cm 

∵ Δ OAB-Δ OCD 

∴ `(AB)/(CD)=(OB)/(OD)` 

⇒ `8/5=6.4/y` 

⇒` y=(6.4xx5)/8=4 ` 

Hence, DO = 4 cm 

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पाठ 7: Triangles - EXERCISE 7B [पृष्ठ ४००]

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 7 Triangles
EXERCISE 7B | Q 3. | पृष्ठ ४००
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