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प्रश्न
In the given figure, if ∠ADE = ∠B, show that ΔADE ~ ΔABC. If AD = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm and BC = 4.2 cm, find DE.
बेरीज
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उत्तर
Given: ∠𝐴𝐷𝐸= ∠𝐴𝐵𝐶 𝑎𝑛𝑑 ∠𝐴= ∠𝐴
Let DE be X cm
Therefore, by AA similarity theorem, Δ ADE - Δ ABC
⇒ `(AD)/(AB)=(DE)/(BC)`
⇒ `3.8/(3.6+2.1)=x/4.2`
⇒` x=(3.8xx4.2)/5.7=2.8`
Hence, DE = 2.8 cm
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