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प्रश्न
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then

AE = ______ × AB.
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उत्तर
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then

AE = 4 × AB.
Explanation:
∵ AB + BC + CD + DE = AE
⇒ AB + AB + AB + AB = AE
∴ 4AB = AE
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संबंधित प्रश्न
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then

AD = AB + ______
Look at a given figure. Mark a point

- A which is in the interior of both ∠1 and ∠2.
- B which is in the interior of only ∠1.
- Point C in the interior of ∠1.
Now, state whether points B and C lie in the interior of ∠2 also.
In the following figure, is AC + CB = AB?

How many points are marked in the following figure?

In the following figure, how many points are marked? Name them.

Use the figure to name Five points.

Draw a rough figure and label it suitably in the following case:
Point P lies on `overline"AB"`.
A point has:
Three or more points lying on the same straight line are called:
Non-collinear points are:
