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प्रश्न
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then

AE = ______ × AB.
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उत्तर
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then

AE = 4 × AB.
Explanation:
∵ AB + BC + CD + DE = AE
⇒ AB + AB + AB + AB = AE
∴ 4AB = AE
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संबंधित प्रश्न
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then

Mid point of AE is ______
In the following figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then

Mid point of CE is ______
The number of common points in the two angles marked in the following figure is ______.

The number of common points in the two angles marked in the following figure is ______.

State the mid points of all the sides of figure.

In the following figure, is AB + AC = CB?

In the following figure, is AB + BC = CA?

In the following figure, how many points are marked? Name them.

In the following figure, how many points are marked? Name them.

In the following figure, how many points are marked? Name them.

