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प्रश्न
In a nuclear reaction
`"_2^3He + _2^3He -> _2^4He +_1^1H +_1^1H + 12.86 Me V` though the number of nucleons is conserved on both sides of the reaction, yet the energy is released. How? Explain.
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उत्तर
In a nuclear reaction, the sum of the masses of the target nucleus `"_2^3He` and the bombarding particle `"_2^3He` may be greater or less than the sum of the masses of the product nucleus `"_2^4He` and the `"_1^1He`. So from the law of conservation of mass-energy some energy (12.86 MeV) is evolved in nuclear reaction. This energy is called Q-value of the nuclear reaction. The binding energy of the nucleus on the left side is not equal to the right side. The difference in the binding energies on two sides appears as energy released or absorbed in the nuclear reaction.
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संबंधित प्रश्न
Write notes on Nuclear fission
Write notes on Nuclear fusion
Explain the processes of nuclear fission and nuclear fusion by using the plot of binding energy per nucleon (BE/A) versus the mass number A
Show that the minimum energy needed to separate a proton from a nucleus with Zprotons and N neutrons is `ΔE = (M_(Z-1,N) + M_B - M_(Z,N))c^2`
where MZ,N = mass of an atom with Z protons and N neutrons in the nucleus and MB = mass of a hydrogen atom. This energy is known as proton-separation energy.
Consider the fusion in helium plasma. Find the temperature at which the average thermal energy 1.5 kT equals the Coulomb potential energy at 2 fm.
Why nuclear fusion reaction is also called thermo-nuclear reaction?
Write one balanced reaction representing nuclear fusion.
Briefly explain the elementary particles present in nature.
For a nuclear fusion process, the suitable nuclei are:
Nuclear fusion reaction that powers the sun involves:
