मराठी

In the given figure, O is the centre of the circle such that ∠AOC = 130°, then ∠ABC =

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प्रश्न

In the given figure, O is the centre of the circle such that ∠AOC = 130°, then ∠ABC =

पर्याय

  • 130°

  •  115°

  • 65°

  • 165°

MCQ
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उत्तर

115°

We have the following information in the following figure. Take a point P on the circle in the given figure and join AP and CP.

Since, the angle subtended by a chord at the centre is twice that of subtended atany part of the circle.

So,  `angleAPC = (angleAOC)/2 = 130/2 = 65°`

Since `squareAPBP` is a cyclic quadrilateral and we known that opposite angles are supplementary.

Therefore,

\[\angle ABC + \angle APC = 180°\]
\[ \Rightarrow \angle ABC + 65° = 180° \]
\[ \Rightarrow \angle ABC = 180° - 65° \]
\[ \Rightarrow \angle ABC = 115°\]

 

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पाठ 15: Circles - Exercise 15.7 [पृष्ठ ११२]

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आर.डी. शर्मा Mathematics [English] Class 9
पाठ 15 Circles
Exercise 15.7 | Q 30 | पृष्ठ ११२

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