Advertisements
Advertisements
प्रश्न
In ΔABC is a right triangle such that ∠C = 90° ∠A = 45°, BC = 7 units find ∠B, AB and AC
Advertisements
उत्तर
Sum of angles in Δle = 180°
∠A + ∠B + ∠C = 180°
45° + ∠B + 90° = 180°
∠B = 180° − 135°
∠B = 45°

From figure `cos B = (BC)/(AB)`
`cos 45^2 = 7/(AB)`
`1/sqrt2 . 7/(AB)`
`AB = 7sqrt2 units`
From figure `sin B = (AC)/(AB)`
`sin 45^@ = (AB)/(7sqrt2)`
`1/sqrt2 = (AC)/(7sqrt2)`
∴ AC = 7 units
APPEARS IN
संबंधित प्रश्न
In Given Figure, find tan P – cot R.

If sin A = `3/4`, calculate cos A and tan A.
In ΔABC, right angled at B. If tan A = `1/sqrt3` , find the value of
- sin A cos C + cos A sin C
- cos A cos C − sin A sin C
State whether the following are true or false. Justify your answer.
The value of tan A is always less than 1.
State whether the following are true or false. Justify your answer.
sec A = `12/5` for some value of angle A.
Prove that `(sin "A" - 2sin^3 "A")/(2cos^3 "A" - cos "A") = tan "A"`
if `sec A = 17/8` verify that `(3 - 4sin^2A)/(4 cos^2 A - 3) = (3 - tan^2 A)/(1 - 3 tan^2 A)`
If `tan theta = 24/7`, find that sin 𝜃 + cos 𝜃
Evaluate the Following
cosec3 30° cos 60° tan3 45° sin2 90° sec2 45° cot 30°
Evaluate the Following
`cot^2 30^@ - 2 cos^2 60^circ- 3/4 sec^2 45^@ - 4 sec^2 30^@`
Evaluate the Following
`4/(cot^2 30^@) + 1/(sin^2 60^@) - cos^2 45^@`
The value of sin² 30° – cos² 30° is ______.
`(sin theta)/(1 + cos theta)` is ______.
Prove that sec θ + tan θ = `cos θ/(1 - sin θ)`.
Proof: L.H.S. = sec θ + tan θ
= `1/square + square/square`
= `square/square` ......`(∵ sec θ = 1/square, tan θ = square/square)`
= `((1 + sin θ) square)/(cos θ square)` ......[Multiplying `square` with the numerator and denominator]
= `(1^2 - square)/(cos θ square)`
= `square/(cos θ square)`
= `cos θ/(1 - sin θ)` = R.H.S.
∴ L.H.S. = R.H.S.
∴ sec θ + tan θ = `cos θ/(1 - sin θ)`
If sec θ = `1/2`, what will be the value of cos θ?
Prove that `tan θ/(1 - cot θ) + cot θ/(1 - tanθ)` = 1 + sec θ cosec θ
If cosec θ = `("p" + "q")/("p" - "q")` (p ≠ q ≠ 0), then `|cot(π/4 + θ/2)|` is equal to ______.
Evaluate 2 sec2 θ + 3 cosec2 θ – 2 sin θ cos θ if θ = 45°.
Evaluate: 5 cosec2 45° – 3 sin2 90° + 5 cos 0°.
