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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

If the solenoid is free to turn about the vertical direction and a uniform horizontal magnetic field of 0.25 T is applied, what is the magnitude of torque on the solenoid when its axis makes an angle

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प्रश्न

If the solenoid is free to turn about the vertical direction and a uniform horizontal magnetic field of 0.25 T is applied, what is the magnitude of torque on the solenoid when its axis makes an angle of 30° with the direction of applied field?

संख्यात्मक
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उत्तर

Given: Magnetic field strength, B = 0.25 T

Magnetic moment, M = 0.6 T−1

The angle θ, between the axis of the solenoid and the direction of the applied field, is 30°.

Formula: τ = MB sin θ

= 0.6 × 0.25 × sin 30°

= 7.5 × 10−2 J

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पाठ 5: Magnetism and Matter - EXERCISES [पृष्ठ १५२]

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एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 5 Magnetism and Matter
EXERCISES | Q 5.4 | पृष्ठ १५२
एनसीईआरटी Physics Part I and II [English] Class 12
पाठ 5 Magnetism and Matter
Exercise | Q 5.6 | पृष्ठ २०१

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