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If the Speed of a Rod Moving at a Relativistic Speed Parallel to Its Length is Doubled - Physics

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प्रश्न

If the speed of a rod moving at a relativistic speed parallel to its length is doubled,

(a) the length will become half of the original value
(b) the mass will become double of the original value
(c) the length will decrease
(d) the mass will increase

थोडक्यात उत्तर
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उत्तर

(c) the length will decrease
(d) the mass will increase


If the speed of a rod moving at a relativistic speed v parallel to its length, its mass \[m = \gamma m_o  = \frac{m_o}{\sqrt{1 - \frac{v^2}{c^2}}}\]

and its length \[l = \frac{l_o}{\gamma} =  l_o \sqrt{1 - \frac{v^2}{c^2}}\]

where \[\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}} =  \left( 1 - \frac{v^2}{c^2} \right)^\frac{- 1}{2}  = 1 + \frac{v^2}{2 c^2} +  .  .  .  > 1\text{ as } v < c\]

If the speed is doubled, its multiplying factor

\[\gamma' = \frac{1}{\sqrt{1 - \frac{4 v^2}{c^2}}} =  \left( 1 - \frac{4 v^2}{c^2} \right)^\frac{- 1}{2}  = 1 + \frac{2 v^2}{c^2} +  .  .  .  > 2\gamma\]

and \[m = \gamma' m_o  > 2\gamma m_o ,   l = \frac{l_o}{\gamma'} < \frac{l_o}{2\gamma}\]

Hence, the mass will increase but more than double and length will decrease but not exactly half of the original values.

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Energy and Momentum
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 25: The Special Theory of Relativity - MCQ [पृष्ठ ४५७]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 25 The Special Theory of Relativity
MCQ | Q 2 | पृष्ठ ४५७

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