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प्रश्न
If `sin θ = 3/5` and θ is an acute angle, find (i) cos θ, (ii) tan θ.
बेरीज
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उत्तर
Given: `sin θ = 3/5`, θ is acute.
Step-wise calculation:
1. Use identity sin2θ + cos2θ = 1.
2. `cos^2θ = 1 - (3/5)^2`
= `1 - 9/25`
= `16/25`
3. θ is acute
⇒ cos θ > 0
So, `cos θ = sqrt(16/25)`
= `4/5`
4. `tan θ = (sin θ)/(cos θ)`
= `(3/5)/(4/5)`
= `3/4`
i. `cos θ = 4/5`
ii. `tan θ = 3/4`
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