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If sin⁡ θ = 3/5 and θ is an acute angle, find (i) cos θ, (ii) tan θ. - Mathematics

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प्रश्न

If `sin θ = 3/5` and θ is an acute angle, find (i) cos θ, (ii) tan θ.

योग
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उत्तर

Given: `sin θ = 3/5`, θ is acute.

Step-wise calculation:

1. Use identity sin2θ + cos2θ = 1.

2. `cos^2θ = 1 - (3/5)^2`

= `1 - 9/25`

= `16/25`

3. θ is acute

⇒ cos θ > 0

So, `cos θ = sqrt(16/25)`

= `4/5`

4. `tan θ = (sin θ)/(cos θ)` 

= `(3/5)/(4/5)`

= `3/4`

i. `cos θ = 4/5`

ii. `tan θ = 3/4`

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अध्याय 17: Trigonometric Ratios - Exercise 17A [पृष्ठ ३५९]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 17 Trigonometric Ratios
Exercise 17A | Q 6. | पृष्ठ ३५९
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