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प्रश्न
Given that `tan θ = 5/12` and angle is an acute angle, find sin θ and cos θ.
बेरीज
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उत्तर
Given: `tan θ = 5/12` and θ is acute.
Step-wise calculation:
1. Let opposite = 5k and adjacent = 12k
So, `tan θ = "Opposite"/"Adjacent"`
= `5/12`
2. Hypotenuse = `sqrt((5k^2) + (12k^2)`
= `sqrt(25k^2 + 144k^2)`
= `sqrt(169k^2)`
= 13k
3. `sin θ = "Opposite"/"Hypotenuse"`
= `(5k)/(13k)`
= `5/13`
4. `cos θ = "Adjacent"/"Hypotenuse"` ...(Both positive because θ is acute.)
= `(12k)/(13k)`
= `12/13`
`sin θ = 5/13, cos θ = 12/13`.
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